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3 years ago

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A disk with a rotational inertia of 2.5 kg-m2 and a radius 1.1 m rotates on a frictionless fixed axis perpendicular to the disk

faces and through its center. A force of 7.7 N is applied tangentially to the rim. The angular acceleration of the disk is _____ rad/s2. Round your answer to the nearest tenth.

1 answer:

soldier1979 [14.2K]3 years ago

7 0

Answer:

3.4 rad/sec^2

Explanation:

rotational inertia = 2.5 kg-m^2 radius = 1.1 m force = 7.7 N

t = rotational inertia * angular acceleration equation 1

also t = force * radius

therefore to calculate angular acceleration equation 1 becomes

f * r = inertia * angular acceleration hence

angular acceleration = f * r / inertia = $\frac{7.7 * 1.1 }{2.5}$ 8.47 / 2.5 = 3.388 ≈ 3.4 rad/sec^2

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