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Arisa [49]
3 years ago
14

A disk with a rotational inertia of 2.5 kg-m2 and a radius 1.1 m rotates on a frictionless fixed axis perpendicular to the disk

faces and through its center. A force of 7.7 N is applied tangentially to the rim. The angular acceleration of the disk is _____ rad/s2. Round your answer to the nearest tenth.
Physics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

3.4 rad/sec^2

Explanation:

rotational inertia = 2.5 kg-m^2   radius = 1.1 m   force = 7.7 N

t = rotational inertia * angular acceleration    equation 1

also t = force * radius

therefore to calculate angular acceleration equation 1 becomes

f * r = inertia * angular acceleration   hence

angular acceleration = f * r / inertia = \frac{7.7 * 1.1 }{2.5}   8.47 / 2.5 = 3.388 ≈ 3.4 rad/sec^2

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The sun’s___and the planet’s___keeps planets moving is___orbits.
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8 0
3 years ago
If a sheep is running at 3.0 m/s with a mass of 60 kg what is its kinetic energy​
borishaifa [10]

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The red shift of visible light waves that is observed by astronomers on Earth is used to determine the
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2 years ago
A mass m = 1.1 kg hangs at the end of a vertical spring whose top end is fixed to the ceiling. The spring has spring constant k
adell [148]

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a) = 10.22 rad/s

b) = 0.35 m

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According to the differential equation of s Simple Harmonic Motion,

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