Answer:
one at the edge
Explanation:
The relation between the linear velocity and the angular velocity is given by
v = r x ω
Where, v be the linear velocity, ω be the angular velocity and r be the radius of the circular path.
As the angular velocity is constant, thus, the linear velocity depends on the radius of circular path.
So, the horse which is near to the edge has maximum radius of circular path in which it is rotating. So, the horse which is at the edge of the merry go round has maximum linear speed.
The total charge on the interior of the conductor is zero.
The total charge on the exterior of the conductor is 8q.
<h3>
Total charge on the interior</h3>
Due to large number of electrons available for conduction in a conductor, most of the electrons moves to surface leaving zero net charge inside the conductor.
Thus, the total charge on the interior of the conductor is zero.
<h3>T
otal charge on the exterior</h3>
The total charge on the exterior of the conductor is calculated as follows;
Q = q + 7q = 8q
Thus, the total charge on the exterior of the conductor is 8q.
Learn more about net charge on interior and exterior of conductors here: brainly.com/question/14653264
Well first of all, a planet doesn't have a semimajor axis, although it's orbit does.
In an orbit with a smaller semimajor axis, the planet moves faster, and its orbital period is shorter.
That's why the International Space Station circles the Earth in less time than the Moon does.
R(parallel) = product/ sum
50×30/50+30
1500/80
18,75 ohms
