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Alecsey [184]
3 years ago
14

Which of the following is an example of +ΔS

Chemistry
2 answers:
S_A_V [24]3 years ago
5 0
If +ΔS means an increase in entropy, or disorder, then a solid subliming into a gas would be an increase in disorder.
Fittoniya [83]3 years ago
5 0

Answer:

A solid being sublimed

Explanation:

Other answer explains it and I took the test and got it correct :)

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Balancing equations<br> I'll give brainliest.
wel

Answer:

You should follow these steps:

Count each type of atom in reactants and products.

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

Repeat steps 1 and 2 until the equation is balanced.

Explanation:

7 0
3 years ago
What is the significant digit in 23.45
klio [65]
If you mean the number of Significant Figures/Digits in 23.45, it would be 4. This is because every single non-zero digit is counted as a significant figure
7 0
3 years ago
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
Using the<br><br>Cahn-Ingold-Prelog
Pavel [41]

Answer:

una ma parra quen est a qui 23^5(-8)

Explanation:

6 0
3 years ago
Zinc reacts with aqueous sulfuric acid to form hydrogen gas: zn(s) h2so4(aq) ? znso4(aq) h2(g) in an experiment, 201 ml of wet h
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The products of reaction are ZnSO4 and H2. Since ZnSO4 is in aqueous form (aq), therefore only H2 and water vapor contributes to the overall total pressure in the system.
Total Pressure = 764 torr = H2 partial pressure + Water partial pressure
Since Water partial pressure is 26.74 torr so,
H2 partial pressure = 737.26 torr = 0.97 atm
3 0
3 years ago
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