Answer:
because it has lighter molecules.
Answer:
a.
9.88
Explanation:
ΔG = - 2.303 RT log Ka
ΔG is change in free energy at temperature T , Ka is equilibrium constant
- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa
- log Ka = 9.88 .
pKa = 9.88 .
Answer:
12.9 g O₂
Explanation:
To find the mass of oxygen gas produced, you need to (1) convert grams KClO₃ to moles KClO₃ (via molar mass from periodic table values), then (2) convert moles KClO₃ to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to match the given value (33.0 g).
Molar Mass (KClO₃): 39.098 g/mol + 35.45 g/mol + 3(15.998 g/mol)
Molar Mass (KClO₃): 122.542 g/mol
2 KClO₃ ---> 2 KCl + 3 O₂
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
33.0 g KClO₃ 1 mole 3 moles O₂ 31.996 g
-------------------- x ------------------- x ----------------------- x ------------------ =
122.542 g 2 moles KClO₃ 1 mole
= 12.9 g O₂
Answer:
48g
Explanation:
2Hg(l) + O₂(g) => 2HgO
44g excess ?
44g/200.59g·mol⁻¹ = 0.219 mole Hg(l) = 0.219 mole HgO(s) produced.*
*Since coefficients are equal for Hg and HgO then the moles of HgO produced is the same as moles Hg used.
Convert 0.219 mole HgO to grams => 0.219mol x 216.95g/mol = 47.512g HgO ≅ 48g (2 sig figs)
A toothpick will be more dense because of its small mass