K shows a decrease in disorder (AS = -120.7 J/(mol-K)) during an exothermic reaction (AH' = -136.9 kJ/mol). Determine whether the reaction is spontaneous or ...
Answer:
Explanation:
To convert from molecules to moles, we must Avogadro's Number.
This number is how many particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, it is molecules of ammonia in 1 mole of ammonia.
Use Avogadro's number as a ratio.
Multiply by the given number of ammonia molecules (6.21*10²⁴)
Flip the fraction so the molecules of ammonia can cancel out.
Multiply to make 1 fraction.
Divide.
The original measurement of molecules had 3 significant figures (6,2 and 1). Therefore we must round our answer to 3 sig figs.
For the answer we found, 3 sig figs is the tenth place. The 1 in the hundredth place tells us to leave the 3 in the tenth place.
There are about <u>10.3 moles of ammonia</u> in 6.21*10²⁴ molecules.
The rate of the reaction, given the data is 0.056 g/min
<h3>What is rate of reaction?</h3>
The rate of a reaction is simply defined as the amount converted per unit time. Mathematically, it can be expressed as:
Rate = amount / time
With the above formula, we can obtain the reaction rate. Details below:
<h3>How to determine the reaction rate</h3>
From the question given above, the following data were obtained:
- Amount of sugar = 1.5 g
- Time = 27 mins
- Reaction rate =?
The reaction rate can be obtained as follow:
Reaction rate = amount / time
Reaction rate = 1.5 / 27
Reaction rate = 0.056 g/min
Thus, the reaction rate is 0.056 g/min
Learn more about reaction rate:
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Answer:
I got 1.14 mol So3 as the answer
hopefully if this could help
Answer:
0.482 ×10²³ molecules
Explanation:
Given data:
Volume of gas = 2.5 L
Temperature of gas = 50°C (50+273 = 323 k)
Pressure of gas = 650 mmHg (650/760 =0.86 atm)
Molecules of N₂= ?
Solution:
PV= nRT
n = PV/RT
n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k
n = 2.15 atm. L /26.52 atm. mol⁻¹.L
n = 0.08 mol
Number of moles of N₂ are 0.08 mol.
Number of molecules:
one mole = 6.022 ×10²³ molecules
0.08×6.022 ×10²³ = 0.482 ×10²³ molecules