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2 years ago

What is the quotient (3x4 + 4x – 15) + (x + 3)?

Mathematics

1 answer:

Hoochie [10]2 years ago

5 0

Answer:

3x-5 and r=0

Step-by-step explanation:

We can do it by long division method the required quotient is 3x-5 and r=0

not 3x-1 , r=1

multiply the divisor with 3x we will get to cancel out the first term of dividend

Now after solving we will get

Now, multiply the divisor by -5 we will get -5x-15 which will cancel the entire dividend.

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Find n(A) for A={0,1,2,3,...,2000}

miskamm [114]

There are 2001 items in that set.

So n(A) = 2001

We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1

where,
m = starting value
n = ending value

In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001

This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)

7 0

2 years ago

Which expression is equivalent to 2(x + 7) – 18x + = ?

Blizzard [7]

Answer:

-16x + 14 or 2(7-8x)

Step-by-step explanation:

= 2(x + 7) – 18x

= 2x + 14 -18x

= -16x + 14

= 2(7-8x)

8 0

2 years ago

What is the slope of a line that passes through the points (3,0) and (3,2)

Alex787 [66]

Answer:

Step-by-step explanation:

5 0

2 years ago

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

2 years ago

Write an equation in slope-intercept form for the line that passes through the

Pavlova-9 [17]

Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
Slope = 3
Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1

Solution: y = 3x + 1

6 0

2 years ago

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