1) Use of density formula to calculate mass of sample, M
D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample
Realize that the sample is the solution.
2) Use ppm concentration to calculate mass of solute (calcium carbonate)
By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.
You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.
Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =
Mass of solute = 0.00374 g of calcium carbonate
Answer: 0.00374 g of calcium carbonate
Answer: 2.4 M
Explanation:
According to the neutralization law,
where,
= molarity of solution = 3.5 M
= volume of solution = 34.3 ml
= molarity of solution = ?
= volume of solution = 50 ml
= valency of = 1
= valency of = 1
Therefore, the concentration of NaOH solution is 2.4 M.
Make a quick chart with each element represented, and count them up. HINT - leave the polyatomic anions together - in this case, PO4
Left Right
1 Ca 3
2 O 1
5 H 2
1 PO4 2
Begin by balancing like finding common denominators of fractions - apply to both sides:
I started by adding a 2 in front of H3PO4 on the left, them 6 in front of H2O on the right. Last, a 3 in front of Ca (OH)2. Then, re-count using the chart format to make sure you're right.
3Ca(OH)2 + 2H3PO4 = Ca3(PO4)2 + 6H2O
Answer:
B
Explanation:
The warmer the water, the more space it takes up, and the lower its density.
7=cells
9= The Central Nervous system
10= not sure