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Effectus [21]
3 years ago
11

Procedure for the experiment.

Chemistry
1 answer:
Elis [28]3 years ago
5 0

Answer:

A solid residue of limestone and some gypsum.

Explanation:

In step 2, some of the limestone and gypsum in the chalk dissolve in the water. When the mixture is filtered, the dissolved substances remain in the water. When the water is boiled off or evaporated, the solid substances remain behind.

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1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?
tatyana61 [14]
<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

  • 10.0 M HNO₃

Prepared solution;

  • Volume of solution as 0.350 L
  • Molarity as 0.40 M

We are required to determine the initial volume of HNO₃

  • We are going to use the dilution formula;
  • The dilution formula is;

M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

    =(0.40 M × 0.350 L) ÷ 10.0 M

   = 0.014 L

But, 1 L = 1000 mL

Therefore,

Volume = 14 mL

Thus, the volume of 10.0 M HNO₃ is 14 mL

5 0
3 years ago
Use the Gizmo to estimate the age of each of the objects below. For these questions, each second in the Gizmo represents 1,000 y
ziro4ka [17]

Answer:

Check the explanation

Explanation:

AT = A0 e(-T/H)

... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.

Substituting what we know, we get...

0.71 = (1) e(-T/5730)

Solve for T...

loge(0.71) = -T/5730

T = -loge(0.71)(5730)

T = 1962 (conservatively rounded, T = 2000)

similarly for all

for aboriginal charcoal

0.28 = (1) e(-T/5730)

Solve for T...

loge(0.28) = -T/5730

T = -loge(0.28)(5730)

T = 7294 (conservatively rounded, T = 7000)

for mayan headdress

0.89 = (1) e(-T/5730)

Solve for T...

loge(0.89) = -T/5730

T = -loge(0.89)(5730)

T = 667 (conservatively rounded, T = 700)

for neanderthal

0.05 = (1) e(-T/5730)

Solve for T...

loge(0.05) = -T/5730

T = -loge(0.05)(5730)

T = 17165 (conservatively rounded, T = 17000)

7 0
3 years ago
All of the following conditions of STP are true except A. 101.3 kPa B. 273.15 K C. 22.4 L D. 3.81 kPa
kaheart [24]
  3.81   kpa  is  the  condition   which  is  not  true   at  STP

According  to  IUPAC  the  standard  temperature  and  pressure  that  is  STP  the  temperature  is   273.15  k  or  0   degrees  celsius .  and  the  absolute  temperature   of   101.325 Kpa   or  1  atm.  In  addition at STP   the  volume of  ideal  gas  is  22.4 
8 0
3 years ago
What is the total number of grams of mg consumed when 0.50 mole of h2 is produced
rosijanka [135]

Answer:

12 grams

<em>Please mark as Brainliest :)</em>

4 0
2 years ago
(6.21×10^3)(0.1050) <br><br>(Scientific Notation)
mel-nik [20]
6.21 x 10^3 = (Move decimal point 3 spaces to the right)

6210

6210 (0.1050)

652.05
3 0
3 years ago
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