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RideAnS [48]
4 years ago
15

The tempertaure at which the pressure of the vapor of a liquid is equal to the external pressure acting on the surface of the li

quid?
Chemistry
1 answer:
djverab [1.8K]4 years ago
8 0

Answer: Boiling point

Explanation:

Boiling point is the temperature where the vapor pressure of a liquid equals the pressure of the gas present above it.

The normal boiling point of a liquid is the temperature at which its vapor pressure is equal to one atmosphere.

Boiling point depends on the intermolecular forces present between the molecules. More are the intermolecular forces, lesser will be the vapor pressure and thus more heat will be supplied to make vapor pressure equal to the atmospheric pressure. Thus higher will be the boiling point.

Normal boiling point for water is 100^0C.

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A 17.6-g sample of ammonium carbonate contains ________ mol of ammonium ions.
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These problems are a bit interesting. :)

First let's write the molecular formula for ammonium carbonate. 

NH4CO3 (Note! The 4 and 3 are subscripts, and not coefficients)

17.6 gNH4CO3

Now to convert to mol of one of our substances we take the percent composition of that particular part of the molecule and multiply it by our starting mass. This is what it looks like using dimensional analyse. 

17.6 gNH4CO3 * (Molar Mass of NH4 / Molar Mass of NH4CO3)

Grab a periodic table (or look one up) and find the molar masses for these molecules! Well. In this case I'll do it for you. (Note: I round the molar masses off to two decimal places)

NH4 = 14.01 + 4*1.01 = 18.05 g/mol
NH4CO3 = 14.01 + 4*1.01 + 12.01 + 3*16.00 = 78.06 g/mol


17.6 gNH4CO3 * (18.05 molNH4 / 78.06 molNH4CO3)
= 4.07 gNH4

Now just take the molar mass we found to convert that amount into moles!

4.07 gNH4 * (1 molNH4 / 18.05 gNH4) = 0.225 molNH4

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