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3 years ago

What is the average acceleration of the object represented in the graph above over the 10 seconds? I know the answer isn’t C

Physics

2 answers:

polet [3.4K]3 years ago

3 0

It's always a good idea to start with the definition of the thing you're trying to find.

This problem is just trying to find out whether you KNOW the definition of acceleration. You may know it, but you haven't used it yet.

Average acceleration = (change in velocity) divided by (total time).

Change in velocity = (end value) minus (start value)

Change in velocity = (20m/s) - 0

Change in velocity = 20 m/s

Time = 10 s

Average acceleration = (20m/s)/(10s)

Average acceleration = 2 m/s^2

horsena [70]3 years ago

3 0

Answer:

2 m/s^2

Explanation:

the slope of A is 4 and B is 0 so (4+0)/2=2

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3 years ago

distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.

a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

$v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s$

So, the speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

4 0

3 years ago

What is the rate at which work is done in lifting a 35-kilogram object vertically at a constant speed of 5.0 meters per second?

svet-max [94.6K]

Answer:

1.75 kW

Explanation:

First, the rate at which work is done is simply termed Power

m = 35kg

v = 5.0 m/s

since the undergoes a vertical motion g = 10 m/s²

F = W = mg = 35×10 = 350 N

Power = Fv = 350×5 = 1750 Watt

8 0

4 years ago