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Murljashka [212]
3 years ago
11

In the hydrologic cycle, water from the ocean ____ into the atmosphere where it can ____ and change back into tiny water droplet

s.
Physics
2 answers:
natka813 [3]3 years ago
3 0
Evaporate, condense ....
mr Goodwill [35]3 years ago
3 0

Answer: In the hydrologic cycle, water from the ocean:

evaporate, it means that the water "transforms" into vapor, so goes in the atmosphere and form clouds.

into the atmosphere where it can:

Condense, it means that the vapor in the atmosphere cold down his temperature and transform in liquid water again.

So evaporation is the process where some liquid changes of phase to a gas state. (here water to vapor of water)

and Condensation is the process where a gas changes of phase to a liquid state. (here vapor of water to water)

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Which of the following best explains why clear-cutting forests is more destructive than selectively cutting down trees in forest
garri49 [273]
<span>The answer is a. cutting trees reduce fertility and eliminates animal habitats. Plant material is essential in maintaing soil fertility. Leaves and branches decay to form humus; removing trees decreases the organic content. Trees are home to many animal species, including birds, insects and amphibians. Some trees are even support or home to other plants. Examples include epiphytes in the rainforest ecosystem. Clear cutting forests disrupts whole communities and ecosystems. </span>
6 0
4 years ago
Read 2 more answers
Eating a banana enables s person to perform about 4×10⁴ J of work. To what vertical height does eating a banana enable a 50kg wo
rjkz [21]

Answer:

80m

Explanation:

potential energy = MGH

p.e = 50 X 10 X h

4x10⁴ = 500 X h

h = 4x10⁴/500

h = 80m

6 0
3 years ago
3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant
lions [1.4K]

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

  • <em>initial velocity of the car, u = 20 m/s</em>
  • <em>acceleration of the car, a = 12 m/s²</em>
  • <em>time of motion of the car, t = 20 s</em>
  • <em>final time = 30 s</em>
  • <em>final acceleration = 2 m/s²</em>

The final time of motion of car before coming to rest is calculated as follows;

v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: brainly.com/question/24874645

3 0
3 years ago
A coin dropped in the lift it takes time 0.5 s to reach the floor when lift is staionary it takes time t when lift is moving up
BARSIC [14]

Answer:

t₁ > t₂

Explanation:

A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then t₁ > t₂,  t₁ = t₂,  t₁ >> t₂ ,  t₂ > t₁

Solution:

Newton's law of motion is given by:

s = ut + (1/2)gt²;

where s is the the distance covered, u is initial velocity, g is the acceleration due to gravity and t is the time taken.

u = 0 m/s, t₁ is the time to reach ground when the light is stationary and t₂ is the time to reach ground when the lift is moving with a constant acceleration a.

hence:

When stationary:

s=\frac{1}{2}gt_1^2\\\\t_1^2=\frac{2s}{g}  \\\\When\ moving\ with\ acceleration(a):\\\\s=\frac{1}{2}(g+a)t_2^2\\\\t_2^2=\frac{2s}{g+a}

Hence t₂ < t₁, this means that t₁ > t₂.

4 0
3 years ago
How fast is a ball going when it hits the ground after being dropped from a
miss Akunina [59]

Hi there!

\large\boxed{\text{C. 17.7m/s}}

Use the following kinematic equation to solve:

vf² = vi² + 2(ad)

Since the initial velocity is 0 m/s because it started at rest, we can eliminate this part of the equation:

vf² = 2ad

Plug in the given acceleration and distance:

vf² = 2(9.8)(16)

vf ≈ 17.7. The correct answer is C.

5 0
3 years ago
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