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katrin2010 [14]
4 years ago
8

The active sections that are located along fault lines are called

Physics
1 answer:
Anuta_ua [19.1K]4 years ago
3 0
<span>B. seismic risks.

</span>The active sections that are located along fault lines are called seismic risks.
NOT:

<span>A. seismic gaps. </span>
<span>C. stress accumulations. </span>
<span>D. recurrence gaps</span>
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If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspe
Readme [11.4K]

The true airspeed will increase and true altitude will increase.

<h3>What is true air speed?</h3>

True airspeed is the airspeed of an aircraft relative to undisturbed air.

It's the aircraft speed relative to the airmass in which it's flying.

<h3>How does outside air temperature affect air speed?</h3>

If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will increase and true altitude will increase.

Thus, the true airspeed will increase and true altitude will increase.

Learn more about true airspeed here: brainly.com/question/13257916

#SPJ1

6 0
2 years ago
For photons of 50 keV, 500 keV, and 5 MeV, what will be the most likely init interaction with tissue?
love history [14]

Answer:

50 KeV

Explanation:

50 KeV will be the most likely initial interaction with tissue.

Because Higher the energy lesser will the interaction with tissues, Because it will penetrate through tissue more easily in a very lesser time Whereas the photon with least energy will take more time to penetrate through the tissue, hence, higher interaction with tissue.

3 0
3 years ago
In Ptolemy's Earth-centered model for the solar system, Venus's phase is never full as viewed from Earth because it always lies
tiny-mole [99]
<h2>Answer: in full phase</h2>

Explanation:

Galileo observed that Venus presented phases (such as those of the moon) together with a variation in size; observations that are only compatible with the fact that <u>Venus rotates around the Sun and not around Earth.  </u>

This is because Venus presented <u>its smaller size when it was in full phase and the largest size when it was in the new one</u>, when it is between the Sun and the Earth.  

In other words: When Venus is in its full phase it is not possible to observe it from the Earth because always in this phase, Venus, the Sun and the Earth are in conjunction (or aligned).  This means <u>the Sun is between Venus and Earth</u>, in the orbit that both planets describe around this star.

Therefore, from the Earth, the Sun covers Venus.

This fact along with other discoveries were presented by Galileo to the Catholic Church (which supported the geocentric theory at that time) as a proof that completely refuted Ptolemy's geocentric system and affirmed Copernicus' heliocentric theory.

7 0
3 years ago
An 89.0 kg fullback moving east with a speed of 5.6 m/s is tackled by an 85.0 kg opponent running west at 2.84 m/s, and the coll
Korolek [52]

Answer:

a. v_f=1.477m/s

b. ΔK=1558.3J

c. E_k=1034.7 J

Explanation:

a).

Momentum conserved

p_{ix}=p_{fx}

m_1*v_1+m_2*v_2=(m_1+m_2)*v_f

v_f=\frac{m_1*v_1+m_2*v_2}{m_1+m_2}

v_f=\frac{89.0kg*5.6m/s+85.0kg*-2.84m/s}{(89.0+85.0)kg}

v_f=1.477m/s

b).

ΔK=K_i-K_f

\frac{1}{2}*m_1*v_1^2+\frac{1}{2}*m_2*v_2^2=\frac{1}{2}*(m_1+m_2)*v_f^2

\frac{1}{2}*89.0kg*(5.6m/s)^2+\frac{1}{2}*85.0kg*(2.84m/s)^2=\frac{1}{2}*(89.0+85.0)kg*(1.447m/s)^2

ΔK=1558.3J

c).

E_k=\frac{1}{2}*89kg*(5.8m/s)^2-\frac{1}{2}*(85+89)kg*(1.44m/s)^2

E_k=1034.7 J

d).

All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.

8 0
3 years ago
Night and day have approximately equal length at what time or times of the year?
Thepotemich [5.8K]

There are two every year – in September and March – when the Sun shines directly on the Equator and the length of day and night is nearly equal.
4 0
3 years ago
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