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igomit [66]
3 years ago
5

If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil

l (1 points) decrease. increase. increase, then decrease. not change.
Physics
2 answers:
maw [93]3 years ago
7 0
I would be decrease. I took this class a couple of months ago. I hope you are satisfied with my answer. 
natita [175]3 years ago
4 0

Answer:

Decrease

Explanation:

The amount of work is the amount of energy required to push or pull an object through a non-zero displacement in the direction of the applied force.

Work = force x displacement

If the amount of force is decreased, the amount of work done also decreases

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What do you think we call this graphical representation based on your prior experience with electric fields and electric field l
slavikrds [6]

Answer:

Explanation:

The strengthcompassion field is proportional to the closeness of the field lines—more precisely, it is proportional to the number of lines per unit area perpendicular to the lines. The direction of the electric field is tangent to the field line at any point in space. Field lines can never cross. These pattern of lines, sometimes referred to as electric field lines, point in the direction that a positive test charge would accelerate if placed upon the line. As such, the lines are directed away from positively charged source charges and toward negatively charged source charges.

Rules for drawing electric field lines

1. Electric field lines are always drawn from High potential to

low potential.

2. Two electric field lines can never intersect each other.

3. The net electric field inside a Conductor is Zero.

4. Electric field line from a positive charge is drawn radially outwards and from a negative charge radially inwards.

5. The density of electric field lines tells the strength of the electric field at that region.

6. Electric field lines terminate Perpendicularly to the surface of a conductor.

A vector quantity has a direction and a magnitude, while a scalar has only a magnitude. You can tell if a quantity is a vector by whether or not it has a direction associated with it.

So, electric fields are vector quantity due to the fact any student can tell you that a compass is used to determine which direction is north.

Since the compass always point northward, then it has a direction and magnitude and so it is a vector quantity

6 0
3 years ago
What will be the change in velocity of a 850kg car if a force of 50,000 N
yKpoI14uk [10]

Answer:

29.412m/s

Explanation:

F=ma where F= force, m= mass, and a=acceleration

we also know that,

a = Δv / t where Δv = change in velocity and t = time

thus F = m ( Δv / t)

50000=850(\frac{v}{0.5})

\frac{50000}{1700}= Δv

29.412m/s=Δv

8 0
3 years ago
an acorn falls from a tree. ignoring air resistance, what forces are on the acorn while it’s falling?
Triss [41]

Answer: gravity

Explanation:

4 0
2 years ago
Inertia law what happens when You are standing on the bus and the bus stops abruptly:
I am Lyosha [343]

Answer:

You will fly forward in the bus until you hit something.

Explanation:

While standing there on the bus, you are traveling at the same speed as the bus. If the bus suddenly stops, you will still be traveling at the same speed you started with. That is until you hit something hard enough or big enough to stop you.

4 0
4 years ago
Read 2 more answers
A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma
Bad White [126]

Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

brainly.com/question/23096032

#SPJ4

5 0
2 years ago
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