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2 years ago

Please help me i need yall will mark brainliest and 30 points!

Chemistry

1 answer:

Amiraneli [1.4K]2 years ago

8 0

Reaction

2Fe(OH)₃ + 3H₂SO₄⇒Fe₂(SO₄)₃ + 6H₂O

because the limiting reactant is Fe(OH)₃, then the moles of all compounds will be based on moles of Fe(OH)₃

mole H₂SO₄ = 3/2 x mole Fe(OH)₃ = 3/2 x 3 mole = 4.5 mole

remaining mole of H₂SO₄ (as an excess reactant) = 6.4 - 4.5 = 1.9 mole

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Depression in freezing point of is related to molality as:

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Where

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depression in freezing point = 5.5-3.9 = 1.6°C

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Read 2 more answers

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Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

$Number \, of \, moles, n = \frac{Mass}{Molar \ mass} = \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl$

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Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

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