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alina1380 [7]
3 years ago
11

Simplify: 12 + 2 x 3 + ( 43 - 12) 68 54 70 18

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0
I got 49 hope that will help.
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The length, with, and height of a rectangular prism can be represented by the expressions (x+3),(x+7),and(x-1). Write an express
joja [24]

Answer: 6x² + 36x + 22

Step-by-step explanation:2 faces  (x + 3) by (x + 7), area of both these faces 2(x+3)*(x + 7)

2 faces  (x + 3) by (x - 1), area of both these faces 2(x+3)*(x - 1)

2 faces  (x -1 ) by (x + 7), area of both these faces 2(x-1)*(x + 7)

Whole surface area is

2(x+3)*(x + 7) + 2(x+3)*(x - 1) + 2(x-1)*(x + 7) =

=2(x² + 3x +7x +21) + 2(x² +3x -x - 3) + 2(x² - x +7x -7)=

=2x² + 20x +42 + 2x² + 4x - 6 + 2x² + 12x -14 =

= 6x² + 36x + 22

5 0
2 years ago
Read 2 more answers
Hello can someone please help me with this.
otez555 [7]

Answer:

a)

T` {-4,-2}

R` {2,8}

S` {-9,4}

Step-by-step explanation:

x, y → y,x

5 0
2 years ago
Please help differentiate this!!!!!!!!!
vlada-n [284]
\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t

\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3  \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}
5 0
3 years ago
Read 2 more answers
Which statement is true?
Archy [21]

Answer:

B? come at me if im wrong

Step-by-step explanation:

7 0
3 years ago
A very large batch of components has arrived at a distributor. The batch can be characterized as acceptable only if the proporti
KatRina [158]

Answer:

c. 0.10

Step-by-step explanation:

Hello!

To accept a batch of components, the proportion of defective components is at most 0.10.

X: Number of defective components in a sample of 10.

This variable has a binomial distribution with parameters n=10 and p= 0.10 (for this binomial experiment, the "success" is finding a defective component)

The distributor will accept the batch if at most two components are defective, symbolically:

P(X≤2)

Using the tables for the binomial distribution you can find the accumulated probability for a sample of n=10 with probability of success of p= 0.10 and number of successes x= 2

P(X≤2)= 0.9298

I hope this helps!

5 0
3 years ago
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