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mylen [45]
3 years ago
9

The element radon is at the opposite end of the range, with the lowest specific heat of all naturally occurring elements. Radon'

s specific heat is 94 J/kg°C. If the
temperature of a 0.34 kg sample of radon is to be raised by 25°C, how much energy will have to be added to the radon?
Physics
1 answer:
allochka39001 [22]3 years ago
5 0

Explanation:

Q = mc∆T

= (0.34 kg)(94 J/kg-°C)(25°C)

= 799 J

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If an object falls from rest and lands 3.2 seconds later, how many<br> meters did it fall
DIA [1.3K]

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

d=\frac{1}{2}*g*t^{2}

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8m/s^{2} , t is the time in seconds

Therefore, d = \frac{1}{2}*9.8*(3.2)^{2}

d= 50.176 ≈ 50.2m

6 0
3 years ago
While an object is in projectile motion (with upward being positive) with no air resistance ct is in projectile motion (with upw
andrew11 [14]

Answer:

The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Explanation:

This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.

Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.

The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.

So, <u>the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.</u>

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3 years ago
Se lanza un cohete en un ángulo de 53° sobre la horizontal con una rapidez inicial de 100 m/s. El cohete se mueve por
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Answer:

Explanation:

v = u + at

v₃ = 100 +30.0(3.00) = 190 m/s

s = vt + ½at²

y₃ = (100sin53)(3.00) + ½(30sin53)(3.00²) = 347.4 m

x₃ = (100cos53)(3.00) + ½(30cos53)(3.00²) = 261.8 m

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s = (v² - u²) / 2a

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b) t₁ = 3.00 s

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t = 3.00 + 15.5 + 17.6 = 36.1 s

c) xmax = 261.8 + (190cos53)( 15.5 + 17.6) = 4,047 m

3 0
3 years ago
Which term describes the point when two objects reach the same temperature and there is no longer a transfer of energy through h
yaroslaw [1]
The term you need to know is equilibrium. Technically it means that heat gained = heat lost. Normally in beginning chemistry classes the evidence for this condition is a stable temperature. 
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How are air temperature and air pressure related?
geniusboy [140]

Answer: Whenever the temperature is high, the air pressure is low.

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5 0
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