It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>
NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
Take the square root of both side
<h3>t = 6.42 s</h3>
Therefore, it will take 6.42 s for the ball to get to the ground.
Learn more: brainly.com/question/24903556
(d) Acceleration is a vector quantity
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
Answer:
4.167m/sec
Explanation:
1km=1000m
1.5km=1500m
1min=60sec
6min=360sec
In 360sec they travel 1500m
In 1 sec they travel=1500m/360
1sec=4.167m
Answer:
See description
Explanation:
With the given information we have:
the interval is ![[0,\pi ]](https://tex.z-dn.net/?f=%5B0%2C%5Cpi%20%5D)
now the mass 
has the given expression:
we will use the formula for a line integral and let:
therefore we have:
we solve the integral:
