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babymother [125]
3 years ago
14

I. Determine the mass of reactants and products that will be needed if one mole of P4(s) reacts completely, as follows

Chemistry
1 answer:
natka813 [3]3 years ago
7 0

Answer:

I. <em>Reagents: </em>

P₄= 123.88 g

H₂ = 12 g

<em>Products: </em>

PH₃= 135.88g

II. Total reagents = 135.88 g

Total products = 135.88 g

III. The<em> principle of conservation of mass</em>

Explanation:

I. First, the molar masses of all reagents and all reaction products are calculated:

• mP₄ = 4 x mP = 4 x 30.97g = <em>123.88 g / mol </em>

• mH₂ = 2 x mH = 2 x 1.00g = <em>2 g / mol </em>

• mPH₃ = 4 x mH + m P = 3 x 1.00g + 30.97g = <em>33.97 g / mol </em>

Having the equation balanced, it can be seen that in order <u><em>for one mole to react completely of P₄, 6 moles of H₂ must react, and 4 moles of PH₃ will be produced</em></u>. With the molar masses, we obtain the reacting masses of each reagent and the mass of product that is formed:

<em>Reagents: </em>

P₄: 1 mol ≡ 123.88 g

H₂: 6 moles ≡ 12 g

<em>Products: </em>

PH₃: 4 moles ≡135.88g

II. We add the total mass of the reagents:

<em>Total reagents</em> = mP₄ + mH₂ = 123.88 g + 12 g =<em> 135.88 g </em>

As the reaction product is only PH₃,<em> the total mass of products is </em><em>135.88 g</em>

<em />

III.<em> </em>It is seen that the mass of reagents necessary to produce the reaction is equal to the mass of product obtained. Therefore, the principle illustrated with this example is <u><em>the principle of conservation of mass</em></u>, it says that “<em>In an isolated system, during any ordinary chemical reaction, the total mass in the system remains constant, that is, the mass Consumption of reagents is equal to the mass of the products obtained</em> ”

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<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

  • Ca = 1
  • C = 1
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So the number of oxygen atoms = 3

mass of Oxygen :

\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g

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3 years ago
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Mass of cylinder + liquid = 26.414g

Mass of the liquid = 26.414 — 23.731

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Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC
sesenic [268]

Answer:

a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

%IC = (1 - e^{-0.25*(x_A - x_B)^2}) *100%

Where x_A - x_B is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. x_{Ti} = 1.5

x_{O} = 3.5

%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})*100%

%IC = 63.2%

b. x_{Zn} = 1.6

x_{Te} = 2.1

%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})*100%

%IC = 11.7%

c. x_{Cs} = 0.7

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})*100%

%IC = 73.3%

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x_{Sb} = 1.9

%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})*100%

%IC = 0.995 %

e. x_{Mg} = 1.2

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})*100%

%IC = 55.5%

4 0
3 years ago
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