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nevsk [136]
3 years ago
6

21. Compare and contrast beta particles to the electrons that surround neutral atoms.

Physics
1 answer:
stiv31 [10]3 years ago
6 0
Beta particles come from the nucleus. Electrons are found around the nucleus.
Beta particles normally travel very fast out of a nucleus in a straight line. Electrons normally orbit the nucleus of an atom.

They both have the same mass and the same charge.
You might be interested in
1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?​
DIA [1.3K]

Answer:

5 m/s is the answer so yeah

5 0
3 years ago
Which is the correct order from least amount of atomic (particle) movement to the most amount of atomic particle movement?
babymother [125]

Answer: particles movement in solid< particles movement in liquids< particles movement in gases.

Explanation:

Atoms are very small, it is not easily seen even with the help of light microscopes. However, We use multiple models of atoms toexplain describe particles of an atom behaviour.

In solids, the particles are packed together tightly in an ordered arrangement. The particles only vibrate about their position in the structure because the particles are held together too strongly to allow movement. Thereby,making the particles MOVE THE LEAST

In liquids, the particles are close together and they move with random motion in the container. The particles move rapidly in all directions but there is more colision between itself even more than particles in gases. This means that the particles here are MORE FASTER THAN THAT OF THE SOLID.

Particles in gases move the FASTEST, more than the particles in solids and liquids. Although, the average speed of the particles depends on their mass and the temperature.

8 0
3 years ago
A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the
antoniya [11.8K]
Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

Answer: 12.5 m/s

6 0
3 years ago
a parent swings a 18.5 kg child in a circle of radius 1.05m, making 5 revolutions in 13.4s. what centripetal acceleration does t
Zolol [24]

Answer: 0.146 m/s^{2}

Explanation:

The <u>centripetal acceleration</u> a_{c} of an object moving in a uniform circular path is given by the following equation:

a_{c}=\frac{V^{2}}{r}  (1)

Where:

V is the tangential velocity

r=1.05 m is the radius of the circle

On the other hand, the tangential velocity  is expressed as:

V=\omega r (2)

Where \omega is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:

\omega=\frac{5 rev}{13.4 s}=0.37 rev/s (3)

Substituting (3) in (2):

V=(0.37 rev/s)(1.05 m) (4)

V=0.39 m/s (5)

Substituting (5) in (1):

a_{c}=\frac{(0.39 m/s)^{2}}{1.05 m}  (6)

Finally:

a_{c}=0.146 m/s^{2}  

6 0
3 years ago
Read 2 more answers
I would like to know why this is the correct answer
Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

\tt \sum F=m.a

The mass used in state 1 and 2 remains the same, at 1.5 kg

  • state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

8 0
2 years ago
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