Here in all such collision type question we can use momentum conservation as we can see that there is no external force on this system
![m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}](https://tex.z-dn.net/?f=m_1v_%7B1i%7D%20%2B%20m_2v_%7B2i%7D%20%3D%20m_1v_%7B1f%7D%20%2B%20m_2v_%7B2f%7D)
as we know that
![m_1 = 5 kg](https://tex.z-dn.net/?f=m_1%20%3D%205%20kg)
![m_2 = 2 kg](https://tex.z-dn.net/?f=m_2%20%3D%202%20kg)
![v_{1i} = 2.8 m/s](https://tex.z-dn.net/?f=v_%7B1i%7D%20%3D%202.8%20m%2Fs)
![v_{2i} = 0 m/s](https://tex.z-dn.net/?f=v_%7B2i%7D%20%3D%200%20m%2Fs)
now from above equation we have
![5(2.8) + 2(0) = m_1v+ m_2v](https://tex.z-dn.net/?f=5%282.8%29%20%2B%202%280%29%20%3D%20m_1v%2B%20m_2v)
![14 = (5+ 2) v](https://tex.z-dn.net/?f=14%20%3D%20%285%2B%202%29%20v)
![v = 2 m/s](https://tex.z-dn.net/?f=v%20%3D%202%20m%2Fs)
so the speed of combined system is 2 m/s
Explanation:
the object will begin to move
Answer:
Explanation:
Projectile Motion. Projectile motion is different than free fall: it involves two dimensions instead of one. ... Balls traveling in two dimensions, only one of which experiences acceleration, require two sets of equations: one set for the x-direction and the other for the y-direction.
Amount of work done is zero and so power = 0 watts.
<u>Explanation:</u>
Power is the rate at which work is done, or W divided by delta t. Since the barbell is not moving, the weightlifter is not doing work on the barbell.Therefore, if the work done is zero, then the power is also zero.It may seem unusual that the data given in question is versatile i.e. A weightlifter exerts an upward force on a 1000-N barbell and holds it at a height of 1 meter for 2 seconds. But, still the answer is zero watts , this was a tricky question although conceptual basis of question was good! Power is dependent on amount of work done which is further related to displacement and here the net displacement is zero ! Hence, amount of work done is zero and so power = 0 watts.