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MakcuM [25]
3 years ago
6

To determine the age of fairly recent fossils and organic artifacts, it is possible to analyze the amounts of the isotopes 14C a

nd 14N, because over time the 14C—which originated in the atmosphere—breaks down into 14N. What net change occurred for this to happen?
Chemistry
1 answer:
dolphi86 [110]3 years ago
3 0

Answer: The net change in the atoms is the conversion of a neutron to a proton, turning Carbon (6 protons) into Nitrogen (7 protons).

Explanation:

Carbon-14, generated from the atmosphere, has 6 protons and 8 neutrons. That's where the 14 comes from, called the mass number, is the sum of protons and neutrons (6+8=14).

Carbon-14 is radioactive and decays by beta decay. That means one of its neutrons spontaneously turns into a proton, an electron, and a neutrino, according to:

^{14} C \rightarrow\ ^{14} N\ +\ e^-  +\ neutrino

After that, the atom has 7 protons and 7 neutrons, maintaining its mass number but changing its atomic number from 6 to 7, turning into Nitrogen.

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Why is Anton Von Leeuwenhoek important in the cell theory?​
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Answer:

He was the first scientist to observe and describe bacteria and protozoa by looking at a drop of water from a pound under a microscope. He also was the one to build the first compound microscope.

Hope this helps :)

4 0
3 years ago
Material use make car tyres and chewing gum?
Ulleksa [173]

Answer:

Rubber

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3 0
3 years ago
Which of the following describes a solution of 1 gram of salt dissolved in 500 mL of water?
Greeley [361]

Answer:

B

Explanation:

Homogeneous= all particles are dissolved thoroughly

Solute= 1 gram of salt

Solvent= 500 mL water

8 0
2 years ago
First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta
Klio2033 [76]

Rate equation for first order reaction is as follows:

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}

Here, k is rate constant of the reaction, t is time of the reaction, A_{0} is initial concentration and A_{t} is concentration at time t.

The rate constant of the reaction is 0.1 day^{-1}.

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c)  Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

5 0
2 years ago
Which element has the largest density at stp
MArishka [77]
I believe it is Sodium. I could be wrong though.
8 0
2 years ago
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