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balu736 [363]
3 years ago
10

If 120.4 grams of reactant completely breaks down (decomposes) to produce 106.4 grams of chlorine. What mass of nitrogen gas cou

ld be expected? *
Chemistry
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

m_{nitrogen}=14g

Explanation:

Hello,

In this case, since we are talking about a chemical reaction in which a compound having nitrogen and chlorine is decomposed into chlorine and nitrogen, we must remember that the law of conservation of mass must be obeyed, for that reason, we notice that the mass of the whole reactants must equal the mass of the whole products, as shown below:

m_{reactants}=m_{products}

Next, we know there is only one single reactant and products are constituted by both chlorine and nitrogen:

m_{reactant}=m_{chlorine}+m_{nitrogen}

In such a way, we can compute the mass of nitrogen as shown below:

m_{nitrogen}=m_{reactant}-m_{chlorine}=120.4g-106.4g\\\\m_{nitrogen}=14g

Best regards.

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Complete combustion of 7.40 g of a hydrocarbon produced 22.4 g of CO2 and 11.5 g of H2O. What is the empirical formula for the h
cluponka [151]
<span>C2H5 First, you need to figure out the relative ratios of moles of carbon and hydrogen. You do this by first looking up the atomic weight of carbon, hydrogen, and oxygen. Then you use those atomic weights to calculate the molar masses of H2O and CO2. Carbon = 12.0107 Hydrogen = 1.00794 Oxygen = 15.999 Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087 Now using the calculated molar masses, determine how many moles of each product was generated. You do this by dividing the given mass by the molar mass. moles H2O = 11.5 g / 18.01488 g/mole = 0.638361 moles moles CO2 = 22.4 g / 44.0087 g/mole = 0.50899 moles The number of moles of carbon is the same as the number of moles of CO2 since there's just 1 carbon atom per CO2 molecule. Since there's 2 hydrogen atoms per molecule of H2O, you need to multiply the number of moles of H2O by 2 to get the number of moles of hydrogen. moles C = 0.50899 moles H = 0.638361 * 2 = 1.276722 We can double check our math by multiplying the calculated number of moles of carbon and hydrogen by their respective atomic weights and see if we get the original mass of the hydrocarbon. total mass = 0.50899 * 12.0107 + 1.276722 * 1.00794 = 7.400185 7.400185 is more than close enough to 7.40 given rounding errors, so the double check worked. Now to find the empirical formula we need to find a ratio of small integers that comes close to the ratio of moles of carbon and hydrogen. 0.50899 / 1.276722 = 0.398669 0.398669 is extremely close to 4/10, so let's reduce that ratio by dividing both top and bottom by 2 giving 2/5. Since the number of moles of carbon was on top, that ratio implies that the empirical formula for this unknown hydrocarbon is C2H5</span>
3 0
3 years ago
A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution
artcher [175]

Answer:

660kcal

Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.  

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:  

3.3L * (1000mL / L) * (5g/100mL)= 165 g.

If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.

6 0
3 years ago
What does the host mean when he says that the acid has "donated a proton" to the water?
weqwewe [10]

Answer:

Option B

Explanation:

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These always reffers to strong acid where the dissociation is 100% completed.

In a weak acid, dissociation is not 100% complete, that's why we have an equilibrium.

HA (l) + H₂O (l)  ⇄  H₃O⁺ (aq) +  A⁻(aq)                   Ka

5 0
3 years ago
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

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From Raoults law:

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P(2-propanol) = 45.2 torr × 0.45

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but the total pressure = sum of individual pressures

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y1 = P1 / total pressure

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cheers, i hope this helps.

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Answer:

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  • The other Formulas do not follow this 'General Formula'
8 0
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