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uranmaximum [27]
3 years ago
12

Select the true statement for the following reaction: N2 + 3 H2 → 2 NH3 1. Each N atom is reduced from 0 to +3. Each H atom is o

xidized from 0 to −1. 2. Each N atom is reduced from 0 to −3. Each H atom is oxidized from 0 to +1. 3. Each N atom is oxidized from 0 to +3. Each H atom is reduced from 0 to −1. 4. Each N atom is oxidized from 0 to −3. Each H atom is reduced from 0 to +1. 5. Each N atom is reduced from +1 to −3. Each H atom is oxidized from +1 to 0. 6. Each N atom is oxidized from +1 to +3. Each H atom is reduced from +1 to 0. 7. Each N atom is oxidized from 0 to −6. Each H atom is reduced from 0 to +2. 8. Each N atom is reduced from 0 to −6
Chemistry
1 answer:
ELEN [110]3 years ago
7 0

Answer: option 2

Explanation: each nitrogen is reduced from zero to -3 and Each H is Oxidised from 0 to +1

Since oxidation no of Nitrogen in molecular N2 is always zero and for H2 also zero.

In NH3, x+3(+1)=0

X+3=0

X=-3

And and hydrogen shows +1 Oxidation no when it is combined with non metal(like N,O,cl) and with -2 with metal like Na,Ca etc.

And zero in molecular form H2.

You might be interested in
PC13 ionic or covalent
Juli2301 [7.4K]

Answer:

The bond between Phosphorus and Chlorine in PCl3 is covalent as chlorine needs one electron and phosphorus has metallic character and easily donate electron

5 0
2 years ago
Fe2O3(s) 2Al(s)Al2O3(s) 2Fe(s) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.73
son4ous [18]

Answer:

\Delta S=54.3\frac{J}{K}

Explanation:

Hello!

In this case, for the given reaction, we can write the equation to compute the entropy change as shown below:

\Delta s=2\Delta S_{Fe}+\Delta S_{Al_2O_3}-2\Delta S_{Al}-\Delta S_{Fe_2O_3}

Letting:

\Delta s_{Fe}=27.3\frac{J}{mol*K}\\\\ \Delta s_{Fe_2O_3}=84.4\frac{J}{mol*K}\\\\\Delta s_{Al}=28.3\frac{J}{mol*K}\\\\\Delta s_{Al_2O_3}=51.00\frac{J}{mol*K}

We obtain the entropy change per mole of Fe2O3(s):\Delta s=2*27.3\frac{J}{mol*K}+84.4\frac{J}{mol*K}-2*28.3\frac{J}{mol*K}-51.0\frac{J}{mol*K} \\\\\Delta s=31.4\frac{J}{mol*K}

Finally, the total entropy change when 1.73 moles of Fe2O3(s) react turns out:

\Delta s=31.4\frac{J}{mol*K}*1.73mol\\\\\Delta S=54.3\frac{J}{K}

Best regards!

6 0
3 years ago
Describe the change in the number of valence electrons in the atoms as the bond is successfully formed
leva [86]

Answer:

The number of valence electrons typically becomes 8 (octet rule) with notable exceptions for H, He, Al, B

Explanation:

We should separate this question into two parts for complete clarity. Both principles, however, will be based on the fact that generally atoms tend to have their valence shells filled with octets (8 valence electrons).

  • In molecular compounds, those formed between nonmetals, electron pairs are shared between two atoms. The two or more atoms with any number of valence electrons bond together in a fashion that allows each of them have a total of 8 electrons (except hydrogen and helium, they would need 2 as a maximum, as well as Al and B which form 3 single bonds). This is achieved by forming multiple bonds if required (for example, double or triple bonds rather than just single bonds). Let's say we form a nitrogen gas molecule. Each nitrogen has 5 valence electrons, so they need 3 more electrons to gain an octet. A triple bond will be formed: the three electrons of each nitrogen will be donated into single bonds. This will leave a lone pair on each nitrogen. However, notice that 6 electrons in the 3 bonds yield a total of 6 electrons. This and a lone pair on nitrogen (2 electrons) produce 8 electrons for each nitrogen, as electrons are shared equally.
  • In ionic compounds, those formed between metals and nonmetals, metals tend to lose their valence electrons and nonmetals gain them, again, to have octets. Let's look at a simple example, NaCl. Sodium has one valence electron and chlorine has 7. Sodium would rather lose 1 electron than gain 7 more, as it's energetically more favorable, to gain an octet. This electron lost is accepted by chlorine that initially has 7 electrons and obtains a total of 8 electrons upon acceptance. Now notice that sodium lost its whole shell after giving its 1 electron to chlorine, and its previous shell is already filled with 8 electrons, so each now have an octet.
3 0
3 years ago
Valence electrons of nitrogen​
mixas84 [53]
5 valence electrons
7 0
3 years ago
Read 2 more answers
The condition that a reaction takes place without outside help Choose... Solution in which no more solute can be dissolved in th
11Alexandr11 [23.1K]

Answer:

Difference of the enthalpy (of a system) minus the product of the entropy and absolute temperature

Explanation:

The basis of spontaneity in a chemical reaction is that ∆G must be negative. ¡∆G is known as the change in free energy of a system. If ∆G is negative, then the reaction will occur without any external help (the reaction is spontaneous at room temperature).

∆G is given by;

∆G= ∆H -T∆S

Where;

∆H= change in enthalpy of the system

T= absolute temperature of the system

∆S= change in entropy

Hence; when ∆H -T∆S gives a negative result, the reaction proceeds without any external help.

4 0
3 years ago
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