The pressure of the gas : 1.1685 atm
<h3>Further explanation</h3>
In general, the gas equation can be written
![\large {\boxed {\bold {PV = nRT}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BPV%20%3D%20nRT%7D%7D%7D)
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
n=moles=1.5
V=volumes = 30 L
T=temperature=285 K
The pressure :
![\tt P=\dfrac{nRT}{V}\\\\n=\dfrac{1.5\times 0.082\times 285}{30}\\\\P=1.1685~atm](https://tex.z-dn.net/?f=%5Ctt%20P%3D%5Cdfrac%7BnRT%7D%7BV%7D%5C%5C%5C%5Cn%3D%5Cdfrac%7B1.5%5Ctimes%200.082%5Ctimes%20285%7D%7B30%7D%5C%5C%5C%5CP%3D1.1685~atm)
Answer:
Explanation:
Work function of potassium = 2.29 eV = 3.67 X 10⁻¹⁹ J
So the minimum energy of photon must be equal to 3.67 X 10⁻¹⁹ J .
energy of photon of wavelength λ = hc / λ
where h = 6.67 x 10⁻³⁴
c = 3 x 10⁸
Putting the values in the equation above
6.67 x 10⁻³⁴ x 3 x 10⁸ / λ = 3.67 X 10⁻¹⁹
λ = 6.67 x 10⁻³⁴ x 3 x 10⁸ / 3.67 X 10⁻¹⁹
= 5.452 x 10⁻⁷
= 5452 x 10⁻¹⁰ m
= 5452 A .
Answer:
H3PO4 is stronger than H2PO4- because
H3PO4 dissociation constant is 6.9×10^-3
H2PO4^- dissociation constant is 6.2×10^-8
Answer:
b. 10 mL
Explanation:
First we <u>calculate the amount of H⁺ moles in the acid</u>:
- [H⁺] =
![10^{-pH}](https://tex.z-dn.net/?f=10%5E%7B-pH%7D)
100 mL ⇒ 100 / 1000 = 0.100 L
- 1x10⁻⁵M * 0.100 L = 1x10⁻⁶ mol H⁺
In order to have a neutral solution we would need the same amount of OH⁻ moles.
We can use the pOH value of the strong base:
Then we <u>calculate the molar concentration of the OH⁻ species in the basic solution</u>:
- [OH⁻] =
= 1x10⁻⁴ M
If we use 10 mL of the basic solution the number of OH⁻ would be:
10 mL ⇒ 10 / 1000 = 0.010 L
- 1x10⁻⁴ M * 0.010 L = 1x10⁻⁶ mol OH⁻
It would be equal to the moles of H⁺ so the answer is b.
Answer:
Mg
Explanation:
Mg is above Al on the table meaning it is easier to oxidize.
Fe and Zn are below Al on the table showing they are not as reactive.