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3 years ago

11

The best way to deal with anger is to

1 answer:

Bad White [126]3 years ago

3 0

1.think before you speak
2.once your calm express your anger
3.exercise
4.take time out
5.identify possible solutions
6.stick with I statements (to avoid placing the blame)
7.don’t hold grudges
8.use humor to release tension
9.practice relaxation skills
10.know when to seek help

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A man who weighs 75kg on the surface of the earth whose mass is 6*10^24kg. If the radius of earth is 6480km ,calculate the force

Fiesta28 [93]

Answer:

718.02N is the answer to the question

5 0

3 years ago

What is the critical angle of light traveling from benzene (n=1.501) into air?

Taya2010 [7]

The critical angle formula should be: sin^-1(1/n)

where "n" is 1.501 into the air

<span>The critical angle of light travelling from benzene, happens because the larger angles of incidence from the inside of the benzene has experienced the total internal reflection. </span>

4 0

4 years ago

An ideal gas initially at 4.00atm and 350 K is permitted

Nuetrik [128]

Explanation:

It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is $P_{2}$ and final temperature is $T_{2}$ .

(a) We know that for a monoatomic gas, value of $\gamma$ is \frac{5}{3}[/tex].

And, in case of adiabatic process,

$PV^{\gamma}$ = constant

also, PV = nRT

So, here $T_{1}$ = 350 K, $V_{1} = V$ , and $V_{2} = 1.5 V$

Hence, $\frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}$

$\frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{5}{3} -1}$

$T_{2}$ = 267 K

Also, $P_{1}$ = 4.0 atm, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}$

$\frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{5}{3}}$

$P_{2}$ = 2.04 atm

Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.

(b) For diatomic gas, value of $\gamma$ is \frac{7}{5}[/tex].

As, $PV^{\gamma}$ = constant

also, PV = nRT

$T_{1}$ = 350 K, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}$

$\frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{7}{5} -1}$

$T_{2}$ = 289 K

And, $P_{1}$ = 4.0 atm, $V_{1} = V$ , and $V_{2} = 1.5 V$

$\frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}$

$\frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{7}{5}}$

$P_{2}$ = 2.27 atm

Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.

6 0

4 years ago

Which equations can be used to solve for acceleration? Check all that apply.<br><br>t =

alekssr [168]

Um I would help you but I don’t see the question

8 0

3 years ago

Read 2 more answers

Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con

Vitek1552 [10]

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

Stopping time = 11hrs 30min

Speed = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

Speed = $\frac{distance}{time}$

Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

Input the parameters:

Distance = 910km/hr x 4.5hrs = 4095km

learn more:

Speed brainly.com/question/10048445

#learnwithBrainly

6 0

3 years ago