<span>1.02x10^2 ml
Since molarity is defined as moles per liter, the product of the molarity and volume will remain constant as mole solvent is added. So let's set up an equality to express this
m0*v0 = m1*v1
where
m0, v0 = molarity and volume of original solution
m1, m1 = molarity and volume of final solution.
Solve for v0, then substitute the known values and calculate:
m0*v0 = m1*v1
v0 = (1.75 M * 500 ml)/8.61 M
v0 = (1.75 M * 500 ml)/8.61 M
V0 = 101.6260163
Rounding to 3 significant figures gives 102 ml.
So the original volume of the 8.61 M H2SO4 solution was 102 ml or 1.02x10^2 ml.</span>
2SO2(g)+O2(g)→2 SO3(g), here reaction entropy decreases as the number of gas moles decreases from reactions to products.
HCL(g)+NH3(g)→NH4CL(s), entropy decreases as molecules of gas are converted into solid.
CO2(s)→CO2(g), entropy increases as gas is formed from a solid.
Cao(s)+CO2(g)→Caco3(s), entropy increases as gas is converted into a solid.
True. Coastal regions are affected if it is warm currents over the ocean it make for a higher temperature over the land, if it's a colder current over the ocean it makes for temperatures to drop over land. This happens when the wind blows in from the sea.
Answer:
7.07
Explanation:
HA = weak acid = 0.053
A+ = conjugate base = 0.045
Ka = 7.2x10^-8
Ka = [H+][A-]/HA
7 2x10^-8 = [H+][0.045]/0.053
[H+] = 7.2x10^-8 x 0.053/0.045
= 8.48x10^-8
PH = -log[H+]
= -log[8.48x10^-8]
PH = -[login.48 + log10^-8]
PH = -0.928 - (-8)log10
= 7.07
Answer:
B
Explanation:
Cuz they are supported once discovered and then widely spread then accepted
