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icang [17]
3 years ago
9

A small current element at the origin has a length of and carries a current of in the direction. Find the magnetic field due to

the current element (a) on the axis at (b) on the axis at (c) on the axis at and (d) on the axis at
Physics
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

Answer and Explanation in Attached document

Explanation:

Download docx
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Dr. Eriksson is working on a material called selenium. She is adding a certain number and type of atoms to the selenium, which w
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Answer:

Selenium is a semiconductor

Explanation:

Selenium is a semiconductor.

Elements in the column IV and VI of the periodic table are referred to as Semiconductor.

Selenium lies in the column VI along with Tellurium

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A uniform disk with a 25 cm radius swings without friction about a nail through the rim. If it is released from rest from a posi
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Answer:

Explanation:

During the swing , the center of mass will go down due to which disc will lose potential energy which will be converted into rotational kinetic energy

mgh = 1/2 I ω² where m is mass of the disc , h is height by which c.m goes down which will be equal to radius of disc , I is moment of inertia of disc about the nail at rim , ω is angular velocity .

mgr  = 1/2 x ( 1/2 m r²+ mr²) x ω²

gr  = 1/2 x 1/2  r² x ω² + 1/2r² x ω²

g = 1 / 4 x ω² r + 1 / 2 x ω² r

g = 3  x ω² r/ 4

ω² = 4g /3 r

= 4 x 9.8 /  3 x  .25

= 52.26

ω = 7.23  rad / s .

6 0
3 years ago
Scientists use a substance called Iodine-131 to treat cancer. As Iodine-131 undergoes radioactive decay and emits beta particles
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I think it's strong I'm not to sure I'm sorry if it's wrong

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A speed-time graph is shown below:
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Answer:

It traveled 4 centimeters.

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In a speed versus time graph, the distance travelled is given by the area under the graph.

In this graph we have the following:

- The speed of the object is v = 1 cm/s between time t = 0 s and t = 4 s

- The speed of the object is v = 0 cm/s between time t = 4 s and t = 8 s

Since the speed in the second part is zero, the distance travelled in the second part is zero. So, the only distance travelled by the object is the distance travelled during the first part, which is equal to the area of the first rectangle:

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