Answer:
Ix,Iy,Iz = mr²,9mr²,10mr²
Explanation:
The Question has some missing details.
To solve this question, I'll make the following assumptions.
Distance of particle x = r
Distance of particle y = 3r
Given
The mass of each particles = m
The moment of inertia is calculated by adding product of mass” of each particle with the “square of its distance from the axis of the rotation”.
Ix = m * (r)² = mr²
Iy = m(3r)² = m * 9r² = 9mr²
The distance of z from the axis is r² + (3r)²
So, Iz = m(r² + (3r)²)
Iz = m(r² + 9r²)
Iz = m(10r²)
Iz = 10mr²
So, we have
Ix,Iy,Iz = mr²,9mr²,10mr²
