D. X=130 but im not sure if this is correct
For this case we have that by definition, the equation of a line in the slope-intersection form is:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It is the slope
b: It is the cut point with the y axis
The slope is: ![m = \frac {2} {5}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D)
Thus, the equation is of the form:
![y = \frac {2} {5} x + b](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x%20%2B%20b)
We substitute the given point and find "b":
![-5 = \frac {2} {5} (- 5) + b\\-5 = -2 + b\\-5 + 2 = b\\b = -3](https://tex.z-dn.net/?f=-5%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20%28-%205%29%20%2B%20b%5C%5C-5%20%3D%20-2%20%2B%20b%5C%5C-5%20%2B%202%20%3D%20b%5C%5Cb%20%3D%20-3)
Finally, the equation is:
![y = \frac {2} {5} x-3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x-3)
Answer:
![y = \frac {2} {5} x-3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%20%7B2%7D%20%7B5%7D%20x-3)
Answer:
![R_5=1.12](https://tex.z-dn.net/?f=R_5%3D1.12)
Step-by-step explanation:
We want to calculate the right-endpoint approximation (the right Riemann sum) for the function:
![f(x)=x^2+x](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%2Bx)
On the interval [-1, 1] using five equal rectangles.
Find the width of each rectangle:
![\displaystyle \Delta x=\frac{1-(-1)}{5}=\frac{2}{5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CDelta%20x%3D%5Cfrac%7B1-%28-1%29%7D%7B5%7D%3D%5Cfrac%7B2%7D%7B5%7D)
List the <em>x-</em>coordinates starting with -1 and ending with 1 with increments of 2/5:
-1, -3/5, -1/5, 1/5, 3/5, 1.
Since we are find the right-hand approximation, we use the five coordinates on the right.
Evaluate the function for each value. This is shown in the table below.
Each area of each rectangle is its area (the <em>y-</em>value) times its width, which is a constant 2/5. Hence, the approximation for the area under the curve of the function <em>f(x)</em> over the interval [-1, 1] using five equal rectangles is:
![\displaystyle R_5=\frac{2}{5}\left(-0.24+-0.16+0.24+0.96+2)= 1.12](https://tex.z-dn.net/?f=%5Cdisplaystyle%20R_5%3D%5Cfrac%7B2%7D%7B5%7D%5Cleft%28-0.24%2B-0.16%2B0.24%2B0.96%2B2%29%3D%201.12)
The airplane reaches its maximum height of 81 feet in 12 seconds.
<h3>Behavior of curves</h3>
If y =
, it means that the second derivate is 2 which is positive, then there is a minimum turning point.
If y = -
, it means that the second derivative will be -2 which is negative, then there is a maximum turning point.
Analysis:
h(t) = -
+ 81
By expanding,
h(t) = -(
- 24t + 144) +81
h(t) = -
+ 24t - 144 + 81
h(t) = -
+ 24t - 63
at turning point d/dt(h(t)) = 0
d/dt (h(t)) = -2t +24
-2t +24 = 0
if we differentiate again, second derivative is -2 which is negative, so it is a maximum point.
2t = 24
t = 12 seconds
h(t) at t = 12
h(t) =
+ 24(12) - 63 = 81 feet
In conclusion, the maximum height of the airplane after 12 seconds is 81 feet.
Learn more about minimum and maximum points: brainly.com/question/14993153
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