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dedylja [7]
3 years ago
13

____ is the rate of change in velocity.

Physics
2 answers:
Dimas [21]3 years ago
6 0

<u>Answer:</u>

<u>Acceleration</u> is the rate of change in velocity.

<u>Explanation:</u>

<u>Velocity,v- </u>

"It is the change in a body's displacement or change in speed,d over the time,t."

  • v=s/sec,
  • <u>Units:</u> meter/second.

<u>Acceleration,a-</u>

"When the body has a varying velocity,v across a given time frame,t is called as the acceleration,a."

  • a=v/t,
  • <u>Unit:</u> meter/second².
astra-53 [7]3 years ago
4 0
The answer is Acceleration.
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A box is pulled 6 meters across the ground at a constant velocity by a horizontally applied force of 50 newtons. At the same tim
Vikentia [17]

Answer:

(a) Friction force = 50 N

(b) Work done by friction = 300 j

(c) Net work done = 0 j

Explanation:

We have given that the box is pulled by 6 meter so d = 6 m

Force applied on the box F = 60 N

We have have given that velocity is constant so acceleration will be zero

So to applied force will be utilized in balancing the friction force

So friction force F_{friction}=50N

Work done by friction force W_{friction}=F_{friction}\times d=50\times 6=300j

Work done by applied force W=F\times d=50\times 6=300j

So net work done = 300-300 = 0 j

7 0
3 years ago
Two hoops, starting from rest, roll down identical inclined planes. The work done by nonconservative forces, such as air resiste
Maurinko [17]

Answer: both hoops have the same kinetic energy at the bottom of the incline.

Explanation:

If we assume no work done by non conservative forces (like friction) , the total mechanical energy must be conserved.

K1 + U1 = K2 + U2

If both hoops start from rest, and we choose the bottom of the incline to be the the zero reference level for gravitational potential energy, then

K1 = 0 and U2 = 0

⇒ ΔK = ΔU = m g. h

If both inclines have the same height, and both hoops have the same mass m, the  change in kinetic energy, must be the same for both hoops.

6 0
3 years ago
Two point charges, initially 3 cm apart, are moved to a distance of 1 cm apart. By what factor does the resulting electric force
Solnce55 [7]
The answer is B (1/9).
6 0
3 years ago
A metal disk of radius 6.0 cm is mounted on a frictionless axle. Current can flow through the axle out along the disk, to a slid
Galina-37 [17]

Answer:

0.09 N

Explanation:

We are given that

Radius of disk,r=6 cm=\frac{6}{100}=0.06 m

1 m=100 cm

B=1 T

Current,I=3 A

We have to find the frictional force at the rim between the stationary electrical contact and the rotating rim.

dF=IBdr

dF=IBdr

\tau=rdF=IBrdr

\tau=\int_{0}^{R}IBr dr

\tau=IB(\frac{R^2}{2}

Torque due to friction

\tau=R\times F

Where friction force=F

R\times F=\frac{IBR^2}{2}

F=\frac{IBR}{2}

Substitute the values

F=\frac{3\times 1\times 0.06}{2}

F=0.09 N

7 0
3 years ago
What is the wavelength of a wave if the wave speed is 24 m/s and the frequency is 48 Hz?
Mice21 [21]

Answer:

Wavelength is 0.5

Explanation:

To work it out, you divide Wave speed by the Frequency (24÷48=0.5)

4 0
4 years ago
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