The saw will tip towards the heavy boy. they are centered on the main pivot point so weight dosnt matter but as they go out. mass and weight will determin if the saw moves or not
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If 1.21 m contains 1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.
Answer:
Two types of energy include potential and kinetic energy, which causes motion, which in turn is caused by a force.
Answer:
The net force acting on the bobsled is 300 N.
Explanation:
Given:
Mass of the bobsled is,
Displacement is,
Initial speed is, m/s
Final speed is, m/s
Net acceleration acting on the bobsled can be determined using the following Newton's equation of motion:
Plug in all the given values and solve for acceleration, .
Now, as per Newton's second law, net force is the product of mass and acceleration. So,
Therefore, the net force acting on the bobsled is 300 N.
Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
Given the data in the question;
Hubble's constant;
Age of the universe;
We know that, the reciprocal of the Hubble's constant ( ) gives an estimate of the age of the universe ( ). It is expressed as:
Now,
Hubble's constant;
We know that;
so
Therefore;
Now, we input this Hubble's constant value into our equation;
Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
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