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julsineya [31]
3 years ago
5

What is the empirical formula for C2H4(OH)2??

Chemistry
2 answers:
k0ka [10]3 years ago
8 0

Answer : The empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the empirical formula, we need to determine the least whole number and then divide the whole number by the least whole number.

The given molecular formula is, C_2H_4(OH)_2

In this the least whole number is, 2

So, the empirical formula will be, C_{\frac{2}{2}}H_{\frac{4}{2}}(OH)_{\frac{2}{2}}=C_1H_2(OH)_1

Hence, the empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

zhannawk [14.2K]3 years ago
7 0
<span>Empirical formula for C2H4(OH)2  is</span><span>
C1H3O1

</span>
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<u>Explanation:</u>

The given reaction is the reaction of sodium sulfate with silver nitrate and as the reaction goes we will get the precipitate of Silver sulfate and the balanced reaction is given as,

Na₂SO₄ + 2 AgNO₃→ Ag₂SO₄↓ +  2 NaNO₃

Here silver sulfate is obtained as a precipitate.

Net ionic equation is the equation in which the ions involved in the reaction only taken into account that is ions forming precipitate, whereas the other ions are considered as spectator ions, ions do not involved in the reaction.

Here the net ionic equation is:

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3 years ago
When 29 grams of sodium metal (Na) react with 49 grams of chlorine gas (C1), solid
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Answer:

Explanation:

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29 g of sodium reacts with 35.5 x 29 / 23 g of chlorine

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So 44.76 g of chlorine reacts and 49 - 44.76 = 4.24 g of chlorine is left over .

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