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julsineya [31]
2 years ago
5

What is the empirical formula for C2H4(OH)2??

Chemistry
2 answers:
k0ka [10]2 years ago
8 0

Answer : The empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the empirical formula, we need to determine the least whole number and then divide the whole number by the least whole number.

The given molecular formula is, C_2H_4(OH)_2

In this the least whole number is, 2

So, the empirical formula will be, C_{\frac{2}{2}}H_{\frac{4}{2}}(OH)_{\frac{2}{2}}=C_1H_2(OH)_1

Hence, the empirical formula for C_2H_4(OH)_2 is, CH_2(OH)

zhannawk [14.2K]2 years ago
7 0
<span>Empirical formula for C2H4(OH)2  is</span><span>
C1H3O1

</span>
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\text{reaction fills a} \ \mathbf{100 \  L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \  \text{of oxygen gas, }

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Explanation:

From the correct question above:

The reaction can be represented as:

\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

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                    \mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

I (mol/L)     0.086            0.28                 0              0

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E                 0.086 - 4x     0.28 - 3x      +2x             +6x

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Replacing the value of x, we have:

K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}

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5 0
3 years ago
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posledela

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