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3 years ago

What is the empirical formula for C2H4(OH)2??

Chemistry

2 answers:

k0ka [10]3 years ago

8 0

Answer : The empirical formula for $C_2H_4(OH)_2$ is, $CH_2(OH)$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the empirical formula, we need to determine the least whole number and then divide the whole number by the least whole number.

The given molecular formula is, $C_2H_4(OH)_2$

In this the least whole number is, 2

So, the empirical formula will be, $C_{\frac{2}{2}}H_{\frac{4}{2}}(OH)_{\frac{2}{2}}=C_1H_2(OH)_1$

Hence, the empirical formula for $C_2H_4(OH)_2$ is, $CH_2(OH)$

zhannawk [14.2K]3 years ago

7 0

Empirical formula for C2H4(OH)2 is
C1H3O1

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Among the intermolecular forces,which forces are typically the weakest

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Answer:

The London dispersion force is the weakest intermolecular force. The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.

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3 years ago

A substance that can be broken down into simpler subtend only by a chemical change is aa. homogenous mixtureb. heterogeneous mix

Natasha2012 [34]

Answer:

d. compound

Explanation:

Mixture : It is defined as the substance that is made by the combination of two or more different components which are physically combined.

Homogeneous mixture are the mixtures in which the composition of the substances in it are uniformly mixed. Heterogeneous mixture are the mixtures in which the composition of the substances in it are not uniformly mixed.

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Element : It is a pure substance which is composed of atoms of similar elements.

As discussed above, The different elements in the compounds are chemically bonded and hence, it is the substance which can be broken down into the simpler units when it subtend only by the chemical change.

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4 years ago

The raw water supply for a community contains 18 mg/L total particulate matter. It is to be treated by addition of 60 mg alum (A

s344n2d4d5 [400]

Solution :

Given :

The steady state flow = 8000 $m^3 /d$

$= 80 \times 10^5 \ I/d$

The concentration of the particulate matter = 18 mg/L

Therefore, the total quantity of a particulate matter in fluid $= 80 \times 10^5 \ I/d \times 18 \ mg/L$

$= 144 \times 10^6 \ mg/g$

$= 144 \ kg/d$

If 60 mg of alum $[Al_2(SO_4)_3.14 H_2O]$ required for one litre of the water treatment.

So Alum required for $80 \times 10^5 \ I/d$

$= 80 \times 15^5 \ I/d \times 60 \ mg \ alum /L$

$= 480 \times 10^6 \ mg/d$

or 480 kg/d

Therefore the alum required is 480 kg/d

1 mg of the alum gives 0.234 mg alum precipitation, so 60 mg of alum will give $= 60 \times 0.234 \text{ of alum ppt. per litre}$

$= 14.04$ mg of alum ppt. per litre

480 kg of alum will give = 480 x 0.234 kg/d

= 112.32 kg/d ppt of alum

Daily total solid load is $= 144 \ kg/d + 112.32 \ kg/d$

= 256.32 kg/d

So, the total concentration of the suspended solid after alum addition $= 18 \ mg/L + 60 \times 0.234$

= 32.04 mg/L

Therefore total alum requirement = 480 kg/d

b). Initial pH = 7.4

The dissociation reaction of aluminium hydroxide as follows :

$Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^{-}$

After addition, the aluminium hydroxide pH of water will increase due to increase in $OH^-$ ions.

Therefore, the pH of water will be acceptable range after the addition of aluminium hydroxide.

c). The reaction of $CO_2$ and water as follows :

$CO_2 (g) + H_2O (l) \rightarrow H_2CO_3$

For the atmospheric pressure :

$p_{CO_2} = 3.5 \times 10^{-4} \ atm$

And the pH is reduced into the range of 5.9 to 6.4

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3 years ago

Why are noble metals for example Rhodium, Palladium, Platinum, and Iridium largely used in chemical manufacturing as heterogeneo

Elanso [62]

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3 years ago

Which of the following lists describes characteristics of an acid?

Studentka2010 [4]

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3 years ago