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3 years ago

Sickle cell is anemia is a deadly,recessive disease.How is sickle cell anemia inherited

1 answer:

4 0

Autosomal recessive: cystic fibrosis (CF), sickle cell anemia (SC), Tay Sachs disease. Genes are inherited from our biological parents in specific ways. One of the basic patterns of inheritance of our genes is called autosomal recessive inheritance.

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1. What is the difference between accidental discoveries and scientific investigations?

Alenkasestr [34]

Answer:

the discovery will always need to be tested more where if you're investigating you should already be in a more controlled environment

4 0

2 years ago

How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.

Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

$8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g$

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

$\frac{96.08g}{194.186g}= 0.49478=49.48$

Carbon = 49.48%

Nitrogen: 56.028g

$\frac{56.028g}{194.186g}=0.28853=28.85$

Nitrogen = 28.85%

Oxygen: 31.998g

$\frac{31.998g}{194.186g} =0.16478=16.48$

Oxygen = 16.48%

8 0

3 years ago

Read 2 more answers

Why is it better to allow the solvent front to move almost to the top of a paper strip rather than stopping it at the halfway po

m_a_m_a [10]

Answer:

To allow all the elements or compounds to separate complete.

Explanation:

In chromatography, the compounds need some space and time to separate, one from each other, if you just use the half of the paper strip maybe you will not notice the different spots of compounds. Remember all the substances have different affinity for the solvents, that means, some react very quickly but others need more time as the colors that conform the black color in an ink.

4 0

2 years ago

Find the no. Of electron involved in the electro deposition of 63.5g of cu from a solution of cuso4

sp2606 [1]

This is a redox reaction, meaning reduction-oxidation reaction. This represents the reaction in one side of the electrode in an electrolysis set-up. First, we find the oxidation number of Cu in CuSO4:

(ox. # of Cu)+ ox.# of S + 4(ox.# of oxygen) = 0
(ox. # of Cu) + (6) + 4(-2) = 0
ox. # of Cu = 2+

CuSO4 ---> Cu + SO42-
Cu2+ + SO42- ----> Cu + SO42-
Cu2+ -----> Cu + 2e- (net ionic reaction)

The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of 63.5 g/mol. Then, it would only need 2 electrons.

8 0

3 years ago

The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago