All categories

3 years ago

A box is being pulled to the right. The free body diagram is shown.What is the magnitude of the kinetic frictional force?

Physics

1 answer:

kirill115 [55]3 years ago

4 0

Answer:

A - 0 N

plz mark 5 stars, thanks, and brainliest

You might be interested in

In most cases, how many electrons does it take to completely fill the

Lyrx [107]

Answer: 2

Explanation:

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.

4 0

3 years ago

A concrete piling of 50 kg is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. How much will the wire stretch?

pentagon [3]

Explanation:

It is given that,

Mass of concrete pilling, m = 50 kg

Diameter of wire, d = 1 mm

Radius of wire, r = 0.0005 m

Length of wire, L = 11.2

Young modulus of steel, $Y=20\times 10^{10}\ N/m^2$

The young modulus of a wire is given by :

$Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta L}{L}}$

$Y=\dfrac{F.L}{A\Delta L}$

$\Delta L=\dfrac{F.L}{A.Y}$

$\Delta L=\dfrac{50\ kg\times 9.8\ m/s^2\times 11.2\ m}{\pi (0.0005\ m)^2\times 20\times 10^{10}\ N/m^2}$

$\Delta L=0.034\ m$

So, the wire will stretch 0.034 meters. Hence, this is the required solution.

8 0

3 years ago

You are riding a bicycle home from school. You average 5 meters per second and you are headed south.

olchik [2.2K]

Answer:

(OD) Velocity

Explanation:

Here, the rider is moving with a steady speed (5 m/s) towards south. In this example, we have magnitude as well as direction. Since velocity is a vector quantity, thus we can determine the velocity of the rider.

5 0

3 years ago

Please help.... please guys

Leto [7]

Answer:

unlike poles attract while liked poles repel

Explanation:

These two bar magnet will move away from each other

7 0

2 years ago

A 1250 kg car is pulling a 325 kb trailer. The car and trailer have an acceleration of 2,15m/sec2 together. Determine the net fo

xenn [34]

To solve this problem we will apply the definition of Newton's second law, which says that force is equivalent to body mass by acceleration. In this case the mass of the trailer is 325Kg and its acceleration is $2.15m / s ^ 2$ , so we will proceed to replace and multiply these values to find the net force on this object.

$F= ma$

$F= (325 kg)(2.15 m/s^2)$

F= 698.75N

Under the reference system in which the direction of travel is the positive direction, the direction of the force will be positive.

7 0

3 years ago