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Luda [366]
3 years ago
14

Radioactive plutonium−239 (t1/2 = 2.44 × 105 yr) is used in nuclear reactors and atomic bombs. If there are 3.50 × 102 g of the

isotope in a small atomic bomb, how long will it take for the substance to decay to 1.00 × 102 g, too small an amount for an effective bomb? (Hint: Radioactive decays follow first-order kinetics.) .0000441 yr
Physics
1 answer:
madam [21]3 years ago
7 0

Answer:

t = 4.41 10⁻⁴ years

Explanation:

For this exercise we must use the concept of average life time, which is the time in which the quantity and substance decays in half

    T_{1/2}  = ln2 / λ

Let's calculate the decay constant of plutonium

    λ  = ln2 /  T_{1/2}

    λ  = ln 2 / 2.44 10⁵  

    λ  = 2.84 10⁻⁶  s⁻¹

Radioactive decay is a first order process

     N = No e (-λ   t)

Where N is the number of nuclei, the mass is this by molecular weight

    m = N PM

    m / PM = m₀ / PM e (- λ  t)

    m / m₀ = e (- λ  t)

    -λ  t = ln (m / m₀)

     t = -1 /λ   ln (m/m₀)

     t = - 1 / 2.84 10⁻⁶   ln (0.1 / 0.35)

     t = 4.41 10⁻⁴ years

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Oduvanchick [21]

<u>Answer</u>

D. Base units

<u>Explanation</u>

Basic units are also called fundamental units. They are the standard units agreed internationally for measurements. Most of these measurements are taken from the ground and they are used to derive other units. They are seven in number. There are:

The metre (m)

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6 0
3 years ago
Landslides and mudslides can result from both volcanoes and earthquakes.<br><br> true<br> false
EleoNora [17]
The correct answer would be True!
4 0
3 years ago
Why is it expensive to bring electricity into urban areas?
motikmotik
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8 0
3 years ago
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an aircraft landing on an air craft carrier is brought to a complete stop from an inital velocity of 215km/hr in 2.7 seconds. wh
worty [1.4K]

u= 215 km/hr = 215 * 1000/ 3600 = aprx 60m/s
v=0
t=2.7sec
v= u - at
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Hope it helps
8 0
2 years ago
A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward
AleksandrR [38]

Answer:

(a)  104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.  

The component of F perpendicular to the ramp is Fy.

(a)  

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.  

Resolve F into its x-component from Pythagorean theorem:  

Fx=Fcos30°

Solve for F:  

F= Fx/cos30°  

Substitute for Fx from given data:  

Fx=90 N/cos30°

   =104 N

(b) Resolve r into its y-component from Pythagorean theorem:

     Fy = Fsin 30°

   Substitute for F from part (a):

     Fy = (104 N) (sin 30°)  

          = 52 N  

5 0
2 years ago
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