Since the track is friction less, block’s kinetic energy at the bottom of the track is equal to its potential energy at the top of the track.
PE = 81 * 9.8 * 3.8 = 3016.44 J
Work = 1/2 * 1888 * d^2
PE = Kinetic energy at the base.
1/2 * 1888 * d^2 = 3016.44
d = 1.78 approx 1.8
F = Ke = 1888 * 1.8 = 3398.4N
Answer:
Given force=10lb
L1=4in converting to feet
But 0.08333ft= 1 inch
Then 4 inch is 0.3332
6inch is 0.49998
But hookes law states
F=Kx where F is force,K is the force constant ,X
K=F/X=10/0.3333=30N/m
Integrating this
Integral of 30x with limit 0.333 to 0.5
F=30x^2/2=15x^2substing the limit
F=(15(0.5^2-0.33^2)=2.08ft-lb
Explanation:
You can. But the gravity on the moon is 1/6th the gravity on Earth. This means 300 lbs man would only weigh 50 lbs.
Answer
By F = -kx {-ve just indicating the sign of the force}
=>35 = k x (85-50) x 10^-2
=>k = 100 N/m
Again by F = -kx
Answer:
the extension recorded by the student would be smaller than the actual extension of the spring
