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3 years ago

6

A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height. what is the angle of pr

ojection?

1 answer:

3241004551 [841]3 years ago

5 0

The maximum height is: hmax = v0² sin² α / 2 g<span>
The horizontal range is: x = v0² sin 2 α / g</span>

So we are given that:

x = 14.5 hmax

v0² sin 2 α / g = 14.5 v0² sin² α / 2 g<span>
<span>7.25 sin² α = 2 sin α cos α
<span>7.25 sin α = 2 cos α
7.25 tan α = 2
<span>tan α = 0.27586
<span>α = tan^(-1) 0.27586
α = 15.42°<span>
<span>The angle of projection is 15.42</span></span><span>°</span></span></span></span></span></span>

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