Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?
B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?
Answer:
The frequency change percentage is 9.94%
Explanation:
The frequency shift can be calculated as follows.

= 
=9.95 GHz
So the frequency change seen by the detector is 9.95 - 9.05
% difference
= 9.94%
Answer:
Magnetic field, 
Explanation:
It is given that,
Number of turns, N = 320
Radius of the coil, r = 6 cm = 0.06 m
The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m
Current flowing through the coils, I = 0.5 A
We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :


B = 0.00239 T
or

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is
. Hence, this is the required solution.
Answer:
The acceleration of the mass is 2 meters per square second.
Explanation:
By Newton's second law, we know that force (
), measured in newtons, is the product of mass (
), measured in kilograms, and net acceleration (
), measured in meters per square second. That is:
(1)
The initial force applied in the mass is:


In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to
of the initial force. The acceleration of the mass is:


The acceleration of the mass is 2 meters per square second.
c adding research resources during an investigation
The answer to your question is,
A scientific law.
-Mabel <3