Answer:
here
Explanation:
There are two forces acting upon the skydiver - gravity (down) and air resistance (up). The force of gravity has a magnitude of m•g = (72 kg) •(9.8 m/s/s) = 706 N. ... a 3.25-kg object rightward with a constant acceleration of 1.20 m/s/s if the force of ... of 33.8 kg, how far (in meters) will it move in 1.31 seconds, starting from rest?
Hmmm the only formula i know is v = d * t or volocity = distance * time
The efficiency of the machine is defined as

Here
Work out is the work output and Work in is the work input
To find the Work in we have then


Replacing with our values


The work done by the applied force is
W = Fd
Here,
F = Force
d = Distnace
Rearranging to find F,


F = 129.77N
Therefore the force exerted on the machine after rounding off to two significant figures is 130N