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siniylev [52]
3 years ago
13

Please help homework due tomorrow,,,

Physics
1 answer:
Ad libitum [116K]3 years ago
8 0
Cody ...

Everything on this page is solved with the SAME formula !

             Distance = (speed) x (time) .


Before I get into how to solve each problem, we need to notice that
this whole sheet deals with speed, NOT velocity.

'Velocity' is speed AND THE DIRECTION OF THE  MOTION.
Nothing on this page ever mentions direction, so there's no velocity
anywhere on the page.

Your teacher may not be happy if you talk about this on your homework,
but that's too bad.  Just don't say "velocity" in any of your answers.
Say "speed", and if the teacher complains about that, then it's time to
let the teacher have it with both barrels.
 

1).  Speed = (distance covered) / (time to cover the distance)

2).  Speed = (distance covered) / (time to cover the distance)

3).  Distance  =  (average speed of travel) x (time traveling at that speed)

4).  Time to cover the distance = (distance) / (speed)

5).  Car's     speed = (distance the car covered)        / (time the car took)
      Sprinter speed = (distance the sprinter covered) / (time the sprinter took)

      Calculate the car's speed.
      Calculate the sprinter's speed.
     
      ... Look at the two speeds.
          Decide which one is faster.
     
      ... Subtract the slower one from the faster one. 
          The difference is the answer to "by how much?" .

6).  Distance  =  (speed) x (time spent moving at that speed)

7).  Average speed  =  (TOTAL distance covered)
                                      divided by
                                    (time to cover the TOTAL distance).
   

You might be interested in
V = _____ x 10_____ m/s
Eduardwww [97]

look it up on Google I will give you the answer

8 0
3 years ago
The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.10. What force is required to push it down a 5.0 degree
frosja888 [35]

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

6 0
3 years ago
An object has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s.
taurus [48]

For the object that has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s we have:

1. The velocity of the object is 7.21 m/s.

2. The angle it makes with the horizontal is 33.7°.

1. The velocity of the object can be found as follows:

v = \sqrt{v_{x}^{2} + v_{y}^{2}}

Where:

v_{x}: is the horizontal component of the velocity = 6 m/s

v_{y}: is the vertical component of the velocity = 4 m/s

Hence, the <u>velocity is</u>:

v = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(6 m/s)^{2} + (4 m/s)^{2}} = 7.21 m/s

2. The angle it makes with the <u>horizontal </u>can be calculated with the following trigonometric function:

tan(\theta) = \frac{v_{y}}{v_{x}}

Where:

θ: is the angle it makes with the horizontal

Therefore, the <u>angle is</u>:

\theta = tan^{-1}(\frac{v_{y}}{v_{x}}) = tan^{-1}(\frac{4}{6}) = 33.7

You can learn more about the components of the velocity here: brainly.com/question/2285233?referrer=searchResults

I hope it helps you!

7 0
3 years ago
A superconducting solenoid has 3300 turns per meter and carries 4. 1 ka. Find the magnetic field strength in the solenoid.
WARRIOR [948]

The magnetic field strength is 17 Weber.

<h3>How can we find the value of magnetic field?</h3>

We know, The magnetic field equation is given by:

B= \mu_{0}  \times n \times I

<h3>Given,</h3>

Where, we know,

\mu_{0} = 4\pi  \times 10^{7} \frac{T. m^{2} }{A}= It is the magnetic constant or the permeability of free space.

n = The turn density which is equivalent to number of turns per unit length = 3300 turns per meter = 3300 m^{-1}

I= the amount of current applied to it = 4. 1 kA = 4 × 10^{3} A.

We have to find the magnetic field strength = B

Substituting the known values into the equation gives the strength of the magnetic field, which is:

B= 4\pi \times 10^{7} \times (3300) \times 4.1 \times 10^{3}

B= 17 T.m

B= 17W  [We know, 1 Tesla.meter = 1 Weber]

So, from the above calculation we can see that, The magnetic field strength is 17 Weber.

Learn more about magnetic field :

brainly.com/question/26257705

#SPJ4

4 0
2 years ago
Complete the wording of the Law of Conservation of Matter and Energy (as defined in the text).
Aleks [24]

Answer:

Neither "matter" nor "energy" can be created or destroyed, but they can be changed from one form to the other.

Explanation:

6 0
4 years ago
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