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siniylev [52]
3 years ago
13

Please help homework due tomorrow,,,

Physics
1 answer:
Ad libitum [116K]3 years ago
8 0
Cody ...

Everything on this page is solved with the SAME formula !

             Distance = (speed) x (time) .


Before I get into how to solve each problem, we need to notice that
this whole sheet deals with speed, NOT velocity.

'Velocity' is speed AND THE DIRECTION OF THE  MOTION.
Nothing on this page ever mentions direction, so there's no velocity
anywhere on the page.

Your teacher may not be happy if you talk about this on your homework,
but that's too bad.  Just don't say "velocity" in any of your answers.
Say "speed", and if the teacher complains about that, then it's time to
let the teacher have it with both barrels.
 

1).  Speed = (distance covered) / (time to cover the distance)

2).  Speed = (distance covered) / (time to cover the distance)

3).  Distance  =  (average speed of travel) x (time traveling at that speed)

4).  Time to cover the distance = (distance) / (speed)

5).  Car's     speed = (distance the car covered)        / (time the car took)
      Sprinter speed = (distance the sprinter covered) / (time the sprinter took)

      Calculate the car's speed.
      Calculate the sprinter's speed.
     
      ... Look at the two speeds.
          Decide which one is faster.
     
      ... Subtract the slower one from the faster one. 
          The difference is the answer to "by how much?" .

6).  Distance  =  (speed) x (time spent moving at that speed)

7).  Average speed  =  (TOTAL distance covered)
                                      divided by
                                    (time to cover the TOTAL distance).
   

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A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
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So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
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r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
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The baseball diamond is a square with sides 27.4 m long. If the positive x-axis points from home plate to first base and the pos
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Answer:

What is the magnitude of the player 's displacement? A baseball "diamond" is a square, each side of length 27.4 m, with home plate and if each length of the base is 27.4 m, and the baseball player ran to third base,Then, the baseball player is 27.4 feet away from home plate (where he started)below the horizontal.

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3. an observer is at the midpoint between two coherent in-phase sources of sound of frequency 780 hz. what is the minimum distan
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Answer:

Explanation:

wavelength of sound = velocity / frequency

= 340 / 780

= .4359 m

Let the observer be at equal distance d from in phase source .

let it moves by distance x for destructive interference .

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= d + x - (d - x )

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