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scoundrel [369]
3 years ago
12

A car initally at rest accelerates in a straight line at 3 m/s2 what will be its speed after 2 seconds

Physics
1 answer:
Ainat [17]3 years ago
5 0

Answer

In this Question we have given

acceleration, a=3m/s^2

and time, t=2s

we have to find speed, v=?

Apply newton's Ist equation of motion which goes as

[tex]v =u + at\\ Here   v  is final velocity\\u - initial velocity\\a-acceleration\\t- time[/tex]

In this problem the car starts from rest it means initial velocity, u =0.

Putting values of u, a and t in first equation of motion

v=0+3*2\\v=6m/s

Therefore speed of car after 2 second will be 6m/s

Note: In this type of problems. First check  the units of all quatities. As all the quantities must be first changed into matching units i.e cgs or s.i. units before applying the equation.

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Two blocks with different temperatures had entropies of 10 J/K and 30 J/K before they were brought in contact. What can you say
True [87]

Answer:

a. Ssystem  > 40 J/K

Explanation:

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The entropy of first block = 10 J/K

The entropy of second block = 30 J/K

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6 0
3 years ago
PLEASE HELP!!!!
defon

Answer:

v = 2.45 m/s

Explanation:

first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of cliff = 15 m

Vi = Initial Vertical Velocity = 0 m/s

t = time taken = ?

g = 9.8 m/s²

Therefore,

15 m = (0 m/s) t + (1/2)(9.8 m/s²)t²

t² = (15 m)/(4.9 m/s²)

t = √3.06 s²

t = 1.75 s

Now, we consider the horizontal motion. Since, we neglect air friction effects. Therefore, the horizontal motion has uniform velocity. Therefore,

s = vt

where,

s = horizontal distance covered = 4.3 m

v = original horizontal velocity = ?

Therefore,

4.3 m = v(1.75 s)

v = 4.3 m/1.75 s

<u>v = 2.45 m/s</u>

8 0
3 years ago
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