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scoundrel [369]
2 years ago
12

A car initally at rest accelerates in a straight line at 3 m/s2 what will be its speed after 2 seconds

Physics
1 answer:
Ainat [17]2 years ago
5 0

Answer

In this Question we have given

acceleration, a=3m/s^2

and time, t=2s

we have to find speed, v=?

Apply newton's Ist equation of motion which goes as

[tex]v =u + at\\ Here   v  is final velocity\\u - initial velocity\\a-acceleration\\t- time[/tex]

In this problem the car starts from rest it means initial velocity, u =0.

Putting values of u, a and t in first equation of motion

v=0+3*2\\v=6m/s

Therefore speed of car after 2 second will be 6m/s

Note: In this type of problems. First check  the units of all quatities. As all the quantities must be first changed into matching units i.e cgs or s.i. units before applying the equation.

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The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground
kati45 [8]

Answer:

The time is 0.90 sec.

Explanation:

Given that,

Height = 4.00 m

We need to calculate the time

Using equation of motion

s = ut-\dfrac{1}{2}(-g)t^2

For free fall, u = 0

t =\sqrt{\dfrac{2s}{g}}

Where, s = distance

g = acceleration due to gravity

t = time

Put the value into the formula

t =\sqrt{\dfrac{2\times4.00}{9.8}}

t= 0.90\ sec

Hence, The time is 0.90 sec.

3 0
3 years ago
PNEWTON<br> What is the ist law of motion?
Degger [83]

Answer:

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement about inertia, that objects will remain in their state of motion unless a force acts to change the motion.

Explanation:

mark brainliest answer please

8 0
3 years ago
A hydrogen atom is in its ground state when its orbital electron:
Harlamova29_29 [7]
It is in its ground state when its orbital electron is at its lowest energy amount. 
8 0
3 years ago
Why is acceleration not constant near the speed of light
dmitriy555 [2]

Answer:

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4 0
2 years ago
A sample of an unknown substance has a mass of 0.465 kg. if 3,000.0 j of heat is required to heat the substance from 50.0°c to 1
hammer [34]

The specific heat of the substance will be 0.129 J/g°C.

<h3>What is specific heat capacity?</h3>

The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

The given data in the problem is;

Q is the amount of energy necessary to raise the temperature = 3,000.0 j

M is the mass=  0.465 kg.

Δt is the time it takes to raise the temperature.=50°c

s stands for specific heat capacity=?

Mathematically specific heat capacity is given by;

\rm Q= MC \triangle t \\\\ C = \frac{Q}{M\triangle t} \\\\ C = \frac{3000}{0.465 \triangle 50} \\\\ C =129.0 J/Kg^0C \\\\ C= 0.129 J/g^0C

Hence the specific heat of the substance will be 0.129 J/g°C.

To learn more about the specific heat capacity refer to the link brainly.com/question/2530523

5 0
2 years ago
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