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Luba_88 [7]
3 years ago
7

MOST elements on the periodic table are

Physics
2 answers:
lidiya [134]3 years ago
6 0

Answer:

B

Explanation:

umka21 [38]3 years ago
4 0

MOST elements on the periodic table are metals.

Answer:B

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The wavelengths for visible light rays correspond to which of these options?
elena-s [515]

Answer;

About the size of a virus or a large molecule

Explanation;

Visible light is a form of electromagnetic (EM) radiation, as are radio waves, infrared radiation, ultraviolet radiation, X-rays and microwaves. Generally, visible light is defined as the wavelengths that are visible to most human eyes.

Visible light falls in the range of the EM spectrum between infrared (IR) and ultraviolet (UV). It has frequencies of about 4 × 1014 to 8 × 1014 hertz (Hz) and wavelengths of about 740 nanometers (nm) to 380 nm .

The wavelength of visible light corresponds to the size of a virus or a large molecules which ranges from about 20 to 400 nanometres in diameter.

6 0
3 years ago
Read 2 more answers
A shank has a moment of inertia about the knee joint of 0.18 kg∙m^2. Assume that the quadriceps muscles (vasti and the rectus fe
timofeeve [1]

Answer:

Torque will be equal to 4.176 N-m

Explanation:

It is given moment of inertia about knee joint I=0.18kgm^2

Angular acceleration produced \alpha =23.2rad/sec^2

We e have to find the torque

Torque is equal to \tau =I\alpha , here I is moment of inertia and \alpha is angular acceleration.

Torque will be equal to \tau =0.18\times 23.2=4.176Nm

So torque is equal to 4.176 N-m

8 0
3 years ago
What minimum volume must the slab have for a 75.0 kgkg woman to be able to stand on it without getting her feet wet
Alisiya [41]

V = 0.9375 m3 is minimum volume .

<h3>What is density ?</h3>
  • We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the amount of matter contained therein (its mass).
  • Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small.

Given,

            1000 kg/m3 = density of water

             920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

Learn more about density

brainly.com/question/952755

#SPJ4

6 0
2 years ago
A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the
Liono4ka [1.6K]
The energy of the ski lift at the base is kinetic energy:
K= \frac{1}{2}mv^2
where m is the mass of the ski lift+the people carried, and v=15.5 m/s is velocity at the base.
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is 
U=mgh
where g=9.81 m/s^2 and h is the height at the top of the hill.

So, since the total energy must conserve, we have
U=K
and so
mgh =  \frac{1}{2}mv^2
from which we find the height:
h= \frac{v^2}{2g}= \frac{(15.5m/s)^2}{2\cdot 9.81 m/s^2}=12 m
8 0
3 years ago
Interactive Solution 8.29 offers a model for this problem. The drive propeller of a ship starts from rest and accelerates at 2.3
MAXImum [283]

Answer:

Δθ = 15747.37 rad.

Explanation:

  • The total angular displacement is the sum of three partial displacements: one while accelerating from rest to a certain angular speed, a second one rotating at this same angular speed, and a third one while decelerating to a final angular speed.
  • Applying the definition of angular acceleration, we can find the final angular speed for this first part as follows:

       \omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)

  • Since the angular acceleration is constant, and the propeller starts from rest, we can use the following kinematic equation in order to find the first angular displacement θ₁:

       \omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)

  • Solving for Δθ in (2):

       \theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)

  • The second displacement θ₂, (since along it the propeller rotates at a constant angular speed equal to (1), can be found just applying the definition of average angular velocity, as follows:

       \theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)

  • Finally we can find the third displacement θ₃, applying the same kinematic equation as in (2), taking into account that the angular initial speed is not zero anymore:

       \omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)

  • Replacing by the givens (α, ωf₂) and ω₀₂ from (1) we can solve for Δθ as follows:

      \theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)

  • The total angular displacement is just the sum of (3), (4) and (6):
  • Δθ = θ₁ + θ₂ + θ₃ = 5044.12 rad + 7252 rad + 3451.25 rad
  • ⇒ Δθ = 15747.37 rad.
4 0
3 years ago
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