All categories

2 years ago

Which compound has the strongest hydrogen bonding between its molecules? 1. HBr 2. HF 3. HCl 4. HI

Chemistry

2 answers:

skelet666 [1.2K]2 years ago

4 0

The correct answer is HF

Levart [38]2 years ago

3 0

<span>You can compare the strength of the hydrogen bonding by comparing the electronegativities of the other elements. All the four elements, Br, F, Cl and I belong to the same group in the periodic table: group 17 named halogens. Then the kind of bonding they form is similar: polar covalent. You must know the trend of the electronegativities in the periodic table. Electronegativity decrease when you down across a group. Then the electronegativity of F is the higher of the group (indeed, it is the highest of all the 118 elements) . The higher the electronegativity the stronger the attraction that the halogen attracts the electrons and the stronger the hydorgen bonding. Then, the conclusion is that HF has the strongest hydrogen bonding. </span>

You might be interested in

What happens when sodium and sulfur combine

german

Answer:

It emits hydrogen sulfide...smells like rotten eggs..

ty:)pls let me know whether this is ryt:D

6 0

2 years ago

Read 2 more answers

Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −

kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3) ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca) = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207 KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH of the respective molecules given above,

ΔH = -1270 + (-393.5) - (-1207)

ΔH = -456.5 KJ

8 0

3 years ago

Why is ethanol a member of the homologous series of alcohols but propane is not<br> I’m in the exam!

Mumz [18]

Answer:

I hope it helps..... you can stop at the full-stop

3 0

2 years ago

Many scientists believe that the current period of global warming is related to increased levels of

OlgaM077 [116]

Option B is your answer.

5 0

2 years ago

Read 2 more answers

A common reaction is the formation of butyric acid from butyl alcohol. butyric acid is what causes the odor of rancid butter. ba

Nastasia [14]

Butyl Alcohol on reaction with Oxygen produces Butyric Acid and Water.

The Balance Chemical equation is as follow,

C₄H₉OH + O₂ → C₄H₇O₂H + H₂O

Result:
The equation given in statement is already balanced.

6 0

3 years ago

Read 2 more answers