Answer:
Electric field strengh is a measure of the strength of an electric field at a given point in space, equal to the field would induce on a unit electric charge at that point.
<em>Electric</em><em> </em><em>field</em><em> </em><em>strength</em><em> </em>is also known as <em><u>Electric</u></em><em><u> </u></em><em><u>Field</u></em><em><u> </u></em><em><u>Intensity</u></em><em><u> </u></em><em><u>.</u></em><em> </em>
Explanation:
Electric Field is also defined as <em>force</em><em> </em><em>per</em><em> </em><em>charge</em><em>.</em> The unit will be force unit divided by charge unit. In this case, it will be Newton/Coulomb or N/C.
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Answer:
F(t) = (-6.00 N/s^2)t^2
a(t) = (-3.00 N/s^2)t^2
Because F = ma, the acceleration function is the force function divided by mass (3.50 kg). Because the force is acting to the left, a negative has been introduced.
Take the integral of the acceleration function with the power rule for integrals. Initial velocity is 8.00 m/s
∫a(t) dt=v(t)+v1
v(t)=(-1m/s^4)*t^3+9 m/s
Setting velocity equal to zero and solving for t.
v(t)=0
t^3=9s^3
t=∛9s
=2.08 s
The integral of velocity is position. The object begins at the origin so initial position is 0
∫v(t) dt= x(t)
x(t)=(-0.25m/s^4)*t^4+(9m/s)*t
Plugging the t from step 3 into the x(t) function from step 4. This is the answer to part a.
x(2.08)=14 m
plug 3.50 s into the velocity function from step 2. Speed is the absolute value of velocity. This is the answer to part b.
v(3.5)=(1 m/s^4)(3.5 s)^3+9 m/s
= -18 m/s
speed(3.5 s)=║v(3.5)║=18 m/s
weathering refers to the actual breaking part of the rock or soil. deposition happens when the weathered and eroded material is deposited and finally comes to a stand still.
B.false......absolute magnitude
<span>Measure of the amount of light a star actually gives off.....thats the definition....hop this is helpful</span>
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