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Drupady [299]
2 years ago
6

Identify the formula of the precipitate formed when solutions of sodium perchlorate and nickel(II) nitrate are mixed. If no prec

ipitate will form, answer "no reaction" (without the quotations marks and no capitalization).
Chemistry
1 answer:
kumpel [21]2 years ago
5 0

Answer:

2NaClO₄ (aq) + Ni(NO₃)₂ (aq)  → 2NaNO₃ (aq) + Ni(ClO₄)₂ (aq)

No reaction

Explanation:

NaClO₄ → Sodium perchlorate

Ni(NO₃)₂ →  Nickel (II) nitrate

All the salts from nitrate are soluble salts

All the salts from perchlorate are soluble salts except for the KClO₄

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What kinds of information does a structural formula reveal about the compound it represents
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How many moles of magnesium are needed to react with 3.0 mol of O2?
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2 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

7 0
3 years ago
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