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3 years ago

Why is water considered to be neutral?

Chemistry

2 answers:

deff fn [24]3 years ago

4 0

Explanation:

Because it has a pH of 7, water is considered to be neutral. It is neither an acid nor a base but is the reference point for acids and bases.

Doss [256]3 years ago

3 0

Answer: Clara’s answer is essentially correct; but a little more might help to make the point. To Discuss pH, the concentration of [H+] is given in this way: pH = - log [H+]. In pure water, that concentration is 1 x 10^-7, the log of which is -7, the opposite is 7, thus the pH = 7. The [OH-] is also equal to the [H+], and is an ideal way of saying pure “water is equally as acidic as it is basic”, and is therefore neutral.

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If the human body contains about 50 deciliters of blood, and the blood has about 15 grams of hemoglobin per deciliter, and all o

Tcecarenko [31]

Answer:

The blood will contain 750 grams of O2

Explanation:

Volume of blood in the human body = 15 deciliters

Mass of hemoglobin per deciliter of blood = 15 grams

Mass of hemoglobin in 50 deciliters of blood = 50×15 = 750 grams

Since all the hemoglobin molecules are saturated with O2, mass of O2 in the blood will be the same as mass of hemoglobin molecules in the blood.

Therefore, mass of O2 in the blood is 750 grams

6 0

3 years ago

Read 2 more answers

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

4 years ago

Group 8A of the periodic table contains the A. most reactive nonmetals. B. least reactive nonmetals. C. most reactive metals. D.

aivan3 [116]

Answer: The correct answer is option B.

Explanation: There are 7 elements in group VIII-A. They are Helium (He), Neon(Ne), Argon(Ar), Krypton (Kr), Xenon (Xe), Radon (Rn) and Ununoctium (Uuo). They are considered as a part of group 18.

Metals are shown in purple color in the periodic table. Metalloids as blue color and Non-metals are shown in green color.

Group VIII-A elements have fully filled orbitals and hence are most stable amongst all the elements in the periodic table. They are considered as least reactive elements and as they are categorized as non-metals. So, they are the least reactive non-metals.

Therefore, the correct option is B.