A because if he was a leader he’d take the kick himself and they’re are not all working to kick the ball so it’s not teamwork and it’s not sportsmanship because he isn’t stopping a fight or fixing something between two teams
The force by which earth attracts anobject is know as weight of that particular object.
so,
=》weight ( F ) = mass ( M ) × acceleration ( A )
=》F = 85 × 9.8
( because acceleration due to gravity = 9.8, but sometimes it is taken as approx 10 )
=》F = 833 Newton.
note : if you take acceleration due to gravity as 10 then the weight of the person = 85 × 10 = 850 N )
i hope it helped.....
I would say the atmosphere.
Hope this helps!
Answer:
reading would be 5.413 m.
Explanation:
Given:-
- The actual distance from ruler to an object is d = 24.0 m
- The adiabatic bulk modulus, B = 2.37 *10^9 Pa
- The density of seawater, ρ = 1025 kg/m^3
- The preset value of speed of sound in air, v_th = 343 m/s.
Find:-
Determine the distance reading that the ruler displays.
Solution:-
- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:
v_a = √ (B / ρ )
- Plug in the values in the relationship above and compute v_a:
v_a = √ ( 2.37 *10^9 / 1025 )
v_a = 1520.59038 m/s
- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.
d = v_a*t
t = d / v_a
t = 24.0 / 1520.59038
t = 0.01578 s
- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).
reading = v_th*t
reading = (343)*(0.01578)
= 5.413 m
Answer:
(a) 
(b) 
Explanation:
Given data
The angular velocity of two cylinders ω=257 rad/s
The mass of the two cylinders m=2.88 kg
The radius of small cylinder r₁=0.319 m
The radius of larger cylinder r₂=0.605 m
For Part (a)
The rotational kinetic energy of the cylinder is given by:
Where I is rotational of inertia of solid cylinder about its central axis.
So
Substitute the given values
So
For Part (b)
Substitute the given values
