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3 years ago

14

Comparing X-ray to radio wave, which has a shorter wavelength?

1 answer:

Daniel [21]3 years ago

6 0

Answer:

x-ray

Explanation:

X-rays can penetrate through matter because of their high frequencies while radio waves are not able to do so as much. If you think about it, taking an x-ray requires a lot more energy than for radio waves to allow you to listen to songs on the radio. Hope this helps :)

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DESCRIBE THE FORMATION OF THE SOLAR SYSTEM ACCORDING TO THE NEBULAR THEORY

marishachu [46]

When a cloud of gas and dust in space was disturbed, maybe by the explosion of a nearby star.This explosion made waves in space which squeezed the cloud of gas & dust.

8 0

3 years ago

Q 1. Choose the correct answer.

Natalija [7]

Answer:

Dietz

Explanation:

He is the guy you must justt be smart and know stuff.

7 0

3 years ago

malfutka [58]

Answer:

<em>The penny will hit the ground at 6.39 seconds</em>

Explanation:

<u>Free Fall</u>

The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:

$\displaystyle y=\frac{gt^2}{2}$

Where $g=9.8\ m/s^2$ , and t is the time.

Solving for t:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

Using the value y=200:

$\displaystyle t=\sqrt{\frac{2*200}{9.8}}$

t=6.39 sec

The penny will hit the ground at 6.39 seconds

4 0

3 years ago

Which part of the ear vibrates at the frequency of sound waves

olganol [36]

The ear drum vibrates

6 0

3 years ago

What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic

Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, $\dfrac{dB}{dt}=3\ T/s$

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

$E=N\dfrac{d\phi}{dt}$

$E=N\dfrac{d(BA)}{dt}$

Since, E = IR

$IR=NA\dfrac{dB}{dt}$

$A=\dfrac{IR}{N.\dfrac{dB}{dt}}$

$A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}$

$A=0.188\ m^2$

or

$A=0.19\ m^2$

Area of circular cross section is, $A=\pi r^2$

$r=\sqrt{\dfrac{A}{\pi}}$

$r=\sqrt{\dfrac{0.19}{\pi}}$

r = 0.24 m

So, the radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0

3 years ago