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2 years ago

What type of electromagnetic energy is microwave energy

1 answer:

8 0

Sup cuz u only came back to ask a question cuz. sure cuz. here its cuz. that will be the answer cuz. So the answer could be cuz. Still thinking it might be cuz. Problably i still dont know cuz. Come back cuz. F u Cuz.

Im dead cuz

my finall answer was

Microwaves are a type of electromagnetic radiation, as are radio waves, ultraviolet radiation, X-rays and gamma-rays. Microwaves have a range of applications, including communications, radar and, perhaps best known by most people, cooking.Feb 8, 2018

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Sounds travel faster in Question 1 options: warmer air. cooler air. Temperature does not influence the speed of sound. a vacuum.

olya-2409 [2.1K]

Answer:

warmer air

Explanation:

the particles are more excited which increases the probability that the particles will bump into each other

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2 years ago

A vector has an x component of 25.0 units and a y

sammy [17]

Here is the answer to your question

8 0

3 years ago

The power in an electrical current is given by the equation

Tcecarenko [31]

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

6 0

2 years ago

Read 2 more answers

A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r

sergij07 [2.7K]

Answer:

The workdone is $W = 1.712 *10^{-20 } \ J$

Explanation:

From the question we are told that

The potential difference is $V = 107 mV = 107 *10^{-3} \ V$

Generally the charge on $Na^{+}$ is $Q_{Na^{+}} = 1.60 *10^{-19 } \ C$

Generally the workdone is mathematically represented as

$W = Q_{Na^{+}}V$

=> $W = 1.60 *10^{-19 } * 107 *10^{-3}$

=> $W = 1.712 *10^{-20 } \ J$

8 0

3 years ago

You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r

sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law $n_1sin\theta_1=n_2sin\theta_2$ , where if $n_1$ is the refractive index of the medium containing the incident ray, $\theta_1$ would be the incident angle, and if $n_2$ is the refractive index of the medium containing the refracted ray, $\theta_2$ would be the refraction angle, which we want, so we do: