Answer:
0.908 L.
Explanation:
- Firstly, we should calculate the number of moles of 1.60 g argon.
- n of Ar = mass / molar mass of Ar = (1.60 g) / (39.948 g/mol) = 0.04 mol.
- |t is established and known that the molar volume of a gas at STP (Standard Temperature and Pressure) is equal to 22.4 L for 1 mole of any ideal gas at a temperature of 273.15 K and a pressure of 1.00 atm.
<u><em>using cross multiplication:</em></u>
1.0 mole of Ar gas will occupy → 22.7 L
0.04 mole of Ar gas will occupy → ??? L
∴ The volume occupied by Ar = (0.04 mole) (22.7 L) / (1.0 mole) = 0.908 L.
Answer:
Calculate the frequency of light having wavelength of 456 nm.
1.22*10^8nm
Explanation:
