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zhenek [66]
3 years ago
10

If an atom gains two electrons in a chemical reaction, what is its charge?

Physics
1 answer:
valentina_108 [34]3 years ago
6 0
A. -2


I took the test
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The removal of an embedded gas from a solid object, as happens when formaldehyde in new carpets and furniture is released into t
dezoksy [38]

Answer:

"Offgassing"

Explanation:

According to my research on Kinesiology, I can say that based on the information provided within the question the process being described is known as "Offgassing". In other words this process is defined as when something gives off or releases a chemical, especially a harmful one, in the form of a gas into the air..

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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3 years ago
If a compound forms by ionic bonding, which is not true?
MrRa [10]

Answer:is deez nut;D

Explanation:

because u gay...

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3 years ago
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Evaluate x and y in the equation: E=Cm^xV^y , where E is kinetic energy , m is mass , V is velocity and C is a dimension less co
Korvikt [17]

Answer: Do I look like Einstein

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2 years ago
Arrange the phases of the Moon in order of increasing rising time, from the phase with the earliest rising time at 12:00 a.m. to
ZanzabumX [31]

Answer:

Lets assume the Sun rise time to be 06:00 AM. The rise time of different phases of Moon will be as follows:

12:00 AM : Waning Half

01:00 AM - 05:00 AM : Waning Crescent

06:00 AM : New Moon

07:00 AM - 11:00 AM : Waxing Crescent

12:00 PM :  Waxing Half

01:00 PM - 06:00 PM : Waxing Gibbous

06:00 PM : Full Moon

07:00 PM - 09:00 PM : Waning Gibbous

Explanation:

The Moon is the only celestial object which shows visible changes in its shape and rise and set time over a very short period of time i.e. just one day. One can observe it by observing the Moon daily. One will notice the change easily. This happens because of the geometry of the Sun, Earth and Moon. The Moon doesn't have its own light and shines because of the light of Sun.

At any given time half of the Moon would be illuminated by the Sun but how much of this illuminated portion is facing the Earth decides the phase of the Moon visible from the Earth. Due to this the Moon shows us various phases namely: New, Waxing Crescent, Waxing Half, Waxing Gibbous, Full, Waning Gibbous, Waning Half, Waning Crescent.

Also, the Moon revolves around the Earth completing the orbit in 29.5 Days. Everyday the Moon will change its position in the orbit. Due to this the rising time of Moon shifts by approximately 52 minutes daily. So, the New Moon rises with the Sun and Full Moon rises just after the sunset.

Lets assume the Sun rise time to be 06:00 AM. The rise time of different phases of Moon will be as follows:

12:00 AM : Waning Half

01:00 AM - 05:00 AM : Waning Crescent

06:00 AM : New Moon

07:00 AM - 11:00 AM : Waxing Crescent

12:00 PM :  Waxing Half

01:00 PM - 06:00 PM : Waxing Gibbous

06:00 PM : Full Moon

07:00 PM - 09:00 PM : Waning Gibbous

5 0
3 years ago
An aluminum bar 600mm long, with diameter 40mm long has a hole drilled in the center of the bar.The hole is 30mm in diameter and
Svetradugi [14.3K]

Answer:

Total contraction on the Bar  = 1.22786 mm

Explanation:

Given that:

Total Length for aluminum bar = 600 mm  

Diameter for aluminum bar  = 40 mm

Hole diameter  = 30 mm

Hole length = 100 mm

elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²

compressive load P = 180 KN = 180  × 10³ N

Calculate the total contraction on the bar = ???

The relation used in  calculating the contraction on the bar is:

\delta L = \dfrac{P *L }{A*E}

The relation used in  calculating the total contraction on the bar can be expressed as :

Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)

i.e

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Let's find the area of cross section without the hole and with the hole

Area of cross section without the hole is :

Using A = πd²/4

A = π (40)²/4

A = 1256.64 mm²

Area of cross section with the hole is :

A = π (40²-30²)/4

A = 549.78 mm²

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Total contraction on the Bar  = \dfrac{180 *10^3 \N  }{85*10^3 \ N/mm^2} [\dfrac{500}{1256.64}+ \dfrac{100}{549.78}]

Total contraction on the Bar  = 2.117( 0.398 + 0.182)

Total contraction on the Bar  = 2.117*(0.58)

Total contraction on the Bar  = 1.22786 mm

5 0
3 years ago
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