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Rus_ich [418]
3 years ago
13

In space, astronauts don’t have gravity to keep them in place. That makes doing even simple tasks difficult. Gene Cernan was the

first astronaut who worked on a task outside a spaceship. He said of the experience, “Every time I’d push or turn a valve, it would turn my entire body at zero gravity. I had nothing to hold on to.” As he worked, Gene Cernan’s heart rate and temperature went so high that his fellow astronauts worried that he wouldn’t survive.
Think about routine tasks that astronauts might need to do inside and outside a spaceship. Choose several tasks, and describe the features the ship and spacesuits should have to account for zero gravity as the astronaut completes the task. Use Newton’s laws of motion in your analysis.
Physics
1 answer:
PIT_PIT [208]3 years ago
8 0

going to the toilet, and keeping cleant. no nasty bits floating around but they are weightless !

eating. pushing a fork would push back by newton 3. can't brace themselves to cut

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A 52.0-kg sandbag falls off a rooftop that is 22.0 m above the ground. The collision between the sandbag and the ground lasts fo
sergiy2304 [10]

Answer:

F = 7,916,955.0N

Explanation:

According to newtons second law

Force = mass * acceleration

Given

mass = 52.0kg

distance S = 22.0m

time t = 17.0 ms = 0.017s

We need to get the acceleration first using the formula;

S = ut+ 1/2at²

22 = 0 + 1/2 a(0.017²)

22 = 0.0001445a

a = 22/0.0001445

a = 152,249.13m/s²

The magnitude of the average force exerted will be;

F = ma

F = 52 * 152,249.13

F = 7,916,955.0N

4 0
3 years ago
A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer cylindrical shell of inner radius 3
4vir4ik [10]

Answer:

d) 1.2 mT

Explanation:

Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.

First of all, we observe that:

- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is

I = 15 A

- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).

Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I = 15 A is the current in the conductor

r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field

Substituting, we find:

B=\frac{(4\pi\cdot 10^{-7})(15)}{2\pi(0.0025)}=1.2\cdot 10^{-3}T = 1.2 mT

8 0
3 years ago
During science class, Ava and Justin were discussing the rotation of the Sun and debating over which model would best illustrate
agasfer [191]

Answer:

it would b B

Explanation:

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3 years ago
Why is scalar quantity negative charges is not possible​
umka2103 [35]

Answer:

Scalar quantity can never be Negative. Because scalar has only magnitude not direction. And magnitude can't be negative.

Explanation:

4 0
3 years ago
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Which solid-state component can be used as a switch to turn current on or off?
Papessa [141]
The answer is Transistor. Its a semiconductor device used to amplify or switch electronic signals and electrical power. It is composed of semiconductor material usually with at least three terminals for connection to an external circuit.
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